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Elan Coil [88]
4 years ago
6

Which of these tables represents a linear function?

Mathematics
1 answer:
wlad13 [49]4 years ago
5 0

Answer:

Table 1

Step-by-step explanation:

For a function to be linear, equal changes in x must correspond to equal changes in y.

In all tables, the x values increase by 1, so all changes in x in all 4 tables are 1.

If a function is linear, then all changes in y must be equal.

Table 1:

5 - 6 = -1

4 - 5 = -1

3 - 4 = -1

All changes in y are equal, so the first table is linear.

Table 2:

4 - 3 = 1

6 - 4 = 2

Two differences in y are different, so table 2 is not linear.

Table 3:

6 - 7 = -1

5 - 6 = -1

3 - 5 = -2

Not all differences in y are equal, so table 3 is not linear.

Table 4:

4 - 2 = 2

5 - 4 = 1

Not all differences in y are equal, so table 3 is not linear.

The only table that has equal differences in y corresponding to equal differences in x is Table 1, so only Table 1 shows a linear function.

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tekilochka [14]

Answer:

a

  df =  24.32

b

 df = 30.10

c

 df = 30.7

d

df = 25.5

Step-by-step explanation:

Generally degree of freedom is mathematically represented as

          df =  \frac{ [\frac{ s^2_i }{m} + \frac{ s^2_j }{n} ]^2 }{ \frac{ [ \frac{s^2_i}{m} ]^2 }{m-1 }  +\frac{ [ \frac{s^2_j}{n} ]^2 }{n-1 }  }

Considering a

         a) m = 12, n = 15, s1 = 4.0, s2 = 6.0

           df =  \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{15} ]^2 }{ \frac{ [ \frac{4^2}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{15} ]^2 }{15-1 }  }

         df =  24.32

Considering b

       (b) m = 12, n = 21, s1 = 4.0, s2 = 6.0

          df =  \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{4^4}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 }  }

        df = 30.10

Considering c

      (c) m = 12, n = 21, s1 = 3.0, s2 = 6.0

           df =  \frac{ [\frac{ 3^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{3^4}{12} ]^2 }{12-1 }  +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 }  }

           df = 30.7

Considering c

        (d) m = 10, n = 24, s1 = 4.0, s2 = 6.0

                df =  \frac{ [\frac{ 4^2 }{10} + \frac{ 6^2 }{24} ]^2 }{ \frac{ [ \frac{4^2}{10} ]^2 }{10-1 }  +\frac{ [ \frac{6^2}{24} ]^2 }{24-1 }  }

               df = 25.5

   

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Sedbober [7]

Functions can be used to model real world situations.

<em>(60,10) is a possible solution because the input and output are feasible.</em>

From the question, we understand that:

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This means that 10 families received at least 60 clothes from the 60 people that donated.

The above illustration can happen.

<em>Hence, (60,10) is a possible solution.</em>

Read more about functions at:

brainly.com/question/12431044

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