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3 years ago

Please help will give branliest Math

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

7 0

Answer:

1. the are would be 144

2. 324

3. 900

Step-by-step explanation:

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PLeAsE HeLp Someone

liq [111]

Answer:

yes

Step-by-step explanation:

the answer its 5

5 0

3 years ago

Find the maximum profit and the number of units that must be produced and sold in order to yield the maximum profit. Assume that

vivado [14]

The Profit = Revenue - CostP ( x ) = ( 40 x - 0.5 x² ) - ( 5 x + 15 ) = = 40 x - 0.5 x² - 5 x - 15 = - 0.5 x² + 35 x - 15The maximum profit is when: P`( x ) = 0P ` ( x ) = ( - 0.5 x² + 35 x - 15 ) ` = - x + 35- x + 35 = 0x = 35 ( the number of units )P max = - 0.5 · 35² + 35 · 35 - 15 = - 612.5 + 1225 - 15 = 597.5Answer: The maximum profit is 597.5 and the number of units is 35.

7 0

3 years ago

A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

4 0

3 years ago

I need help with this question

Julli [10]

Answer:

it's 324

Step-by-step explanation:

divide 72 by 4 to get one side, then multiply the side by itself, 18 times 18

3 0

3 years ago

Help with this please 17 points!!

Ivahew [28]

Step-by-step explanation:

S=9

E=2,6,8,10,12

Both 4

The rest place out of circles 1,3,5,7,11

5 0

3 years ago

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