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3 years ago

Rewrite without rational exponents, and simplify, if possible. X^1/3

Mathematics

1 answer:

jeka943 years ago

8 0

Answer:

the answer is 3√x (cube root of x)

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Do you think this Scatter plot is linear or no? I really can't tell.

MrRa [10]

Answer:

I would say no because the dots are all over the place.

Step-by-step explanation:

It keeps going up then down back up and down again?

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3 years ago

The ratio of blue marbles to white marbles Simran's bag is equal to 1 to 2. If there are 20 blue marbles how many white marbles

Nastasia [14]

There are 40 white marbles.

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3 years ago

What is the substitution of -6x-8y=-20 and x+6y=-6

ale4655 [162]

Substitution doesn't work for this, but elimination does.

-6x-8y=-20 +6( x+6y=-6)

-6x-8y=-20 + 6x+36y=-36

-6x and 6x cancel each other, add -8 and 36 to get 28, and -20 and -36 to get -56.

28y=-56

divide by 28 on both sides.

Y= -2

Then substitute y into one of the equations.

x+6(-2)=-6

x-12=-6

x=6

The ordered pair is (6,-2).

5 0

3 years ago

Read 2 more answers

B) Find the value of a^2 + b^2 when a = 3 and b= -2

Zielflug [23.3K]

Answer:

Step-by-step explanation:

a = 3

b = -2

a² + b² = 3² + (-2)²

= 9 + 4

= 13

5 0

3 years ago

Read 2 more answers

Please help with this Math Question...

Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 | 1 4 7 6

1 2 3 0 ← remainder is 0 so x = -2 is a root ⇒ (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}$

$x=\dfrac{-2\pm\sqrt{4-12} }{2}$

$x=\dfrac{-2\pm\sqrt{-8} }{2}$

$x=\dfrac{-2\pm2i\sqrt{2}}{2}$

$x = -1 \pm i\sqrt{2}$

$x = -1 + i\sqrt{2}$ $x = -1 - i\sqrt{2}$

$x - (-1 + i\sqrt{2})=0$ $x - (-1 - i\sqrt{2})=0$

The factors are:

$(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]$

5 0

3 years ago