Answer:
a/b= 2/15
Explanation:
3a +b
----------- = 7/5
b
<h2>now cross multiple both side</h2>
5(3a+b)=7 x b
15a +5b = 7b
15a = 7b-5b
15a = 2b
15a/2b = 1
a/b x 15/2 =1
<h3>multiple both side
by 2/15</h3>
we get,
a/b = 2/15
hope you have no doubt now !
<h2>we get ,</h2>
Answer:
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Answer:
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Explanation:
After defeating the Spanish armada, the British settlers settled along the eastern coast claimed all territory from newfoundland to Florida for the king .
In particular, the planting of a colony at Cuppers Cove (Cupids, Conception Bay) by the London and Bristol Company in 1610 and the southern Avalon plantation in the early 17th century was responsible for the first British settlement in Newfoundland.
Between Trespassed in the south and Salvage in the north, there were at least one family in 30 distinct villages along Newfoundland's east coast by the 1670s.
Following the defeat of Spanish Armada, they settled in Newfoundland, which typically included a period of apprenticeship servitude.
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Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with
.
In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:


The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is <u>1 subtracted by the p-value of Z when X = 30.5</u>, hence:


Z = -2.3
Z = -2.3 has a p-value of 0.0107.
0.0107 = 1.07% probability that more than 30 are single.
More can be learned about the normal distribution at brainly.com/question/24663213