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2 years ago

3c=2(c-1) in a verbal expression

Mathematics

1 answer:

kifflom [539]2 years ago

6 0

9514 1404 393

Answer:

"three times a number is the same as twice the difference of the number and 1"

Step-by-step explanation:

3c is "three times a number"

2(c -1) is "two times the difference of the number and 1"

When writing the description of the right-hand side, one needs to be careful to write it so there is no ambiguity with respect to what is being multiplied by 2. For example, if you say, "two times one less than the number", it is not clear whether that is c -2×1 or 2×(c -1).

A suitable description is ...

three times a number is the same as twice the difference of the number and 1

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What is the Value of X?

skad [1K]

RT = TU
so
m<R = m<U
m<R = 1/2(180 - 114)
m<R = 1/2(66)
m<R = 33
so m<U = m<R = 33

m<SVU = 180 -(31+33)
m<SVU = 180 - 64
m<SVU = 116

x = 180 - 116
x = 64
answer
C. 64

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2 years ago

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Step-by-step explanation:

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2 years ago

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Sladkaya [172]

Answer:

The solution is $\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C$

Step-by-step explanation:

From the question

The function given is $f(x) = \frac{e^{2x}}{ 25 + e^{4x}} dx$

The indefinite integral is mathematically represented as

$\int\limits {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx$

Now let $e^{2x} = u$

=> $\frac{du}{dx} 2e^{2x}$

=> $2 e^{2x}dx = du$

$\int\limits {\frac{e^{2x}}{ 25 + e^{4x}}} \, dx = \int\limits {\frac{1}{ 2(25 + u^2)} } \, du$

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Now substituting for u

$\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C$

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2 years ago

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sp2606 [1]

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2 years ago

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NISA [10]

Answer:

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Step-by-step explanation:

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- •Trix•

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