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BARSIC [14]
3 years ago
10

Solve v^2+2v=0 by factoring

Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

\large \mathfrak{Solution : }

let's factorise :

  • {v}^{2}  + 2v = 0

  • v(v + 2) = 0

now, there are two cases :

case 1 :

  • v = 0

case 2 :

  • v + 2 = 0

  • v =  - 2
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John is doing a fundraiser for school. He needs to sell at least $200 worth of items. John is selling shirts for $10 each and ha
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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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One sample has a mean of and a second sample has a mean of . The two samples are combined into a single set of scores. What is t
Murrr4er [49]

Answer:

a) For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) M = \frac{8*3 + 16*5}{3+5}= 13

c) M = \frac{8*5 + 16*3}{5+3}= 11

Step-by-step explanation:

Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.

a) What is the mean for the combined set if both of the original samples have n=4 scores "

For this case we can use the definition of weighted average given by:

M = \frac{ \bar X_1 n_1 + \bar X_2 n_2}{n_1 +n_2}

And if we replace the values given we have:

M = \frac{8*4 + 16*4}{4+4}= 12

b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5

Using the definition we have:

M = \frac{8*3 + 16*5}{3+5}= 13

c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3

Using the definition we have:

M = \frac{8*5 + 16*3}{5+3}= 11

7 0
3 years ago
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