I need help simplifying -14 1/5-(-13 1/10)

The lowest point in Japan is 4 meters below sea level. The lowest point in Mali is 23 meters above sea level. What is the change

stiv31 [10]

Answer:

19m

Step-by-step explanation:

-4+23 = 19

6 0

2 years ago

HELP PRETTY PLEASE ILL GIVE BRAINLIEST<br> 150% of x is 216. What is x?

Katarina [22]

Answer:
x=144

Step by step:

150% • x = 216

216•100/150

x=144

7 0

2 years ago

Which set of ordered pairs is a function?

melamori03 [73]

Functions can't have multiple y values have the same x value.

[(-5, 1), (-3, 2), (-1, 3) (1, 4), (3, 5)] ** No repeating x-values.

[(-2, 1), (-4, 2), (0,3), (4, 1), (-2,5)]

[(-1, 5), (-1,4), (-1, 3), (-1, 2) (-1, 1)]

[(-6, -4), (-4, -2), (0, 0), (-4, 2) (-6, 4)]

Answer:

[(-5, 1), (-3, 2), (-1, 3) (1, 4), (3, 5)]

4 0

2 years ago

The travel time it takes elevator A to reach height in meters is 0.8h+16 seconds. The travel time it takes elevator B to reach h

Ann [662]

Answer:

Time taken by A = 16 seconds

Time taken by B = 12 seconds

Step-by-step explanation:

Given:

Two elevator and their respective time to reach certain height.

Here time is function of height.

Time taken by elevator A = 0.8(h)+16

Time taken by elevator B = -0.8(h)+12

We have to find the time taken by the elevator to reach ground level.

Accordingly:

We know that ground level the height will be zero meaning that (h=0).

Plugging the h values in the equation we can find the time taken by both the elevators to reach zero height that is the ground level.

⇒ $t_A=0.8h+16$ ⇒ $t_B=-0.8h+12$

⇒ $t_A=0.8(0)+16$ ⇒ $t_B=-0.8(0)+12$

⇒ $t_A=16$ sec ⇒ $t_B=12$ sec

So,

Time taken by elevator A and elevator B to reach the ground is 16 seconds and 12 seconds respectively.

4 0

3 years ago

Text & Tests 1 Junior Cycle Mathematics

yawa3891 [41]

a)

b) i) p(T) = 0.3

b) ii) p(F) = 0.25

b) iii) p(T') = 0.7

b) iv) p(F') = 0.75

b) v) $p(T\cap F)=0.05$

b) vi) $p(T\cup F)=0.5$

Step-by-step explanation:

a)

The Venn diagram is shown in the figure.

In the Venn diagram, we have represented:

- The set of events U, which consists of all the natural numbers from 1 to 20

- The set of events T, which consists of all the numbers multiples of 3

- The set of events F, which consists of all the numbers multiples of 4

We notice that:

- The set T only contains the following numbers: 3,6,9,12,15,18, which are the multiples of 3

- The set F contains only the following numbers: 4,8,12,16,20, which are the multiples of 4

The number 12 is in common between the two sets T and F.

b)

i) After choosing a number from U, here we want to find

P(T)

which represents the probability that the extracted number is part of set T (so, that it is a multiple of 3).

This probability is given by:

$P(T)=\frac{n(T)}{n(U)}$

where

$n(T)$ is the number of numbers in set T

$n(U)$ is the number of numbers in set U

Here we have:

$n(T)=6$ - the multiples of 3 between 1 and 20 are only: 3,6,9,12,15,18

$n(U)=20$ (the numbers from 1 to 20 are 20)

So,

$p(T)=\frac{6}{20}=0.3$

ii)

After choosing a number from U, here we want to find

P(F)

which represents the probability that the extracted number is part of set F (so, that it is a multiple of 4).

This probability here is given by:

$P(F)=\frac{n(F)}{n(U)}$

where:

$n(F)$ is the number of numbers in set F

$n(U)$ is the number of numbers in set U

Here we have:

$n(F)=5$ - the multiples of 4 between 1 and 20 are only: 4,8,12,16,20

$n(U)=20$ (the numbers from 1 to 20 are 20)

Therefore,

$p(F)=\frac{5}{20}=0.25$

iii)

In this part, after a choosing a number from U, we want to find

p(T')

which is the propability of the set of events complementary to T. In other words, we want to find the probability that the extracted number is NOT part of set T.

The complementary probability of a certain set can be found using

$p(T')=1-p(T)$

where

$p(T)$ is the probability of set T to occur

In this problem, as we calculated in part i), we have

p(T) = 0.3

Therefore, the probability of the complementary of T is

$p(T') = 1 - 0.3 = 0.7$

iv)

Similarly to part iii), In this part, after a choosing a number from U, we want to find

p(F')

this is the propability of the set of events complementary to F: so, we want to find the probability that the extracted number is NOT part of set F.

The complementary probability of this set can be found using

$p(F')=1-p(F)$

where:

$p(F)$ is the probability of set F to occur

As we calculated in part ii), here we have

p(F) = 0.25

Therefore, the probability of F not to occur is

$p(F') = 1 - 0.25 = 0.75$

v)

In this part, we want to find

$P(T\cap F)$

which is the probability that after choosing a number from U, this number belongs to both sets T and F. In other words, the probability that the number is multiple of 3 and 4 at the same time.

This probability is given by:

$p(T\cap F) = \frac{n(T\cap F)}{n(U)}$

where

The numerator is the number of numbers between 1 and 20 being at the same time multiple of 3 and 4

The denominator is the number of numbers from 1 to 20

Here we have:

$n(T\cap F) = 1$ , because only 1 number (12) is multiple of 3 and 4 at the same time between 1 and 20

$n(U)=20$

Therefore, this probability is

$p(T\cap F)=\frac{1}{20}=0.05$

vi)

In this part, we want to find

$p(T\cup F)$

which is the probability that after choosing a number from U, this number belongs either to set T or set F. In other words, the probability that the number is either a multiple of 3 or a multiple of 4.

This probability is given by:

$p(T\cup F)=\frac{n(T\cup F)}{n(U)}$