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LiRa [457]
2 years ago
6

What would be the responsibilities of all these employees in the production of this soup if it was served in a restaurant?

Mathematics
1 answer:
expeople1 [14]2 years ago
5 0

Answer:

Could you add the production of this soup if it was served in a restaurant?

Step-by-step explanation:

I'll answer then

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5. The Jones family orders four pizzas to eat. Each pizza is sliced into four parts. How many pizza slices do they get in total?
morpeh [17]

Answer:

16 slices

Step-by-step explanation:

Given :

Number of pizzas ordered = 4

Number of slices per pizza = 4

If 4 pizzas are each sliced into 4 parts ; the we have :

Pizza 1 = 4 slices

Pizza 2 = 4 slices

Pizza 3 = 4 slices

Pizza 4 = 4 slices

Total slices = (4 +4 +4 +4) = 16 slices

7 0
2 years ago
A cone and it’s dimensions are shown in the diagram. What is the volume of the cone in cubic inches?
Nady [450]

Answer:

559.14 (2 decimal places)

Step-by-step explanation:

×jv=\pi r^{2} * \frac{h}{3} \\\pi (5\frac{5}{6} / 2)*(7\frac{1}{2}/3)\\  =559.1359972

3 0
3 years ago
Which is the best description of triangles ABC and DEF?
a_sh-v [17]
C is the answer. Congruent is just a synonym of similar therefore C is the answer.
6 0
3 years ago
Read 2 more answers
6.8 Use the Normal approximation. Suppose we toss a fair coin 100 times. Use the Normal approximation to find the probability th
Maru [420]

Answer:

(a) The probability that proportion of heads is between 0.30 and 0.70 is 1.

(b) The probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

Step-by-step explanation:

Let <em>X</em> = number of heads.

The probability that a head occurs in a toss of a coin is, <em>p</em> = 0.50.

The coin was tossed <em>n</em> = 100 times.

A random toss's result is independent of the other tosses.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 100 and <em>p</em> = 0.50.

But the sample selected is too large and the probability of success is 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of \hat p<em> </em>(sample proportion of <em>X</em>) if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=100\times 0.50=50>10\\n(1-p)=100\times (1-0.50)=50>10

Thus, a Normal approximation to binomial can be applied.

So,  \hat p\sim N(p,\ \frac{p(1-p)}{n})

\mu_{p}=p=0.50\\\sigma_{p}=\sqrt{\frac{p(1-p)}{n}}=0.05

(a)

Compute the probability that proportion of heads is between 0.30 and 0.70 as follows:

P(0.30

                              =P(-4

Thus, the probability that proportion of heads is between 0.30 and 0.70 is 1.

(b)

Compute the probability that proportion of heads is between 0.40 and 0.65 as follows:

P(0.40

                              =P(-2

Thus, the probability that proportion of heads is between 0.40 and 0.65 is 0.9759.

6 0
3 years ago
Simplify 3x + 5x + 14x
navik [9.2K]
Simply collect all the like terms together
So..3+5+14 is 22x
3 0
3 years ago
Read 2 more answers
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