Solution:
Find the LCM of 40 and 30 = 2
12:00 + 2 hours = 2PM
Final Answer:
They will ringt together at 2PM
Answer:
Therefore the population will be maximum when x=30 inches.
Step-by-step explanation:
Given that, the mosquito population is a function of rainfall and can be approximated by the formula
![N(x)= -x^3+45x^2+1000](https://tex.z-dn.net/?f=N%28x%29%3D%20-x%5E3%2B45x%5E2%2B1000)
where x is the number of inches of rainfall.
![N(x)= -x^3+45x^2+1000](https://tex.z-dn.net/?f=N%28x%29%3D%20-x%5E3%2B45x%5E2%2B1000)
Differentiating with respect to x
![N'(x)= -3x^2+90x](https://tex.z-dn.net/?f=N%27%28x%29%3D%20-3x%5E2%2B90x)
Again differentiating with respect to x
![N''(x)=-6x+90](https://tex.z-dn.net/?f=N%27%27%28x%29%3D-6x%2B90)
Now we set N'(x)=0
![-3x^2+90x=0](https://tex.z-dn.net/?f=-3x%5E2%2B90x%3D0)
![\Rightarrow -3x(x-30)=0](https://tex.z-dn.net/?f=%5CRightarrow%20-3x%28x-30%29%3D0)
![\Rightarrow x=0,30](https://tex.z-dn.net/?f=%5CRightarrow%20x%3D0%2C30)
![N''(0)=-6.0+90=90>0](https://tex.z-dn.net/?f=N%27%27%280%29%3D-6.0%2B90%3D90%3E0)
![N''(30)=-6.30+90=-90](https://tex.z-dn.net/?f=N%27%27%2830%29%3D-6.30%2B90%3D-90%3C0)
Since at x=30, N''(x)<0, So at x=30, N(x) has maximum value.
Therefore the population will be maximum when x=30 inches.
Answer:
0.0055 or 11/2000
Step-by-step explanation:
You could have multiplied it by 100 moving the decial poitn to the left 2 place. Or converted it to a fraction then divided the numerator by the denominator.
Hope this helps!!
Probably A, a plane
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