Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

We want
. So
In which


0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Answer:
16
Step-by-step explanation: because 24g reverts 40f so we have to subtract them
and get the answer
Answer:
A. y - 7 = -4(x + 2)
Step-by-step explanation:
Insert the coordinates into the formula with their CORRECT signs. Remember, in the Point-Slope Formula, <em>y</em><em> </em><em>-</em><em> </em><em>y</em><em>₁</em><em> </em><em>=</em><em> </em><em>m</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>x</em><em>₁</em><em>)</em><em>,</em><em> </em>all the negative symbols give the OPPOSITE term of what they really are.
Answer:
3x^2 +8x +3
Step-by-step explanation:
(6x^2 + 8x - 3) - (3x^2 - 6)
Distribute the minus sign
(6x^2 + 8x - 3) - 3x^2 + 6
Combine like terms
3x^2 +8x +3