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nikitadnepr [17]
3 years ago
14

PLEASE HELP

Mathematics
1 answer:
Aloiza [94]3 years ago
7 0
  • Volume=2.7million km^3
  • Base=339milliom km^2

\\ \tt\longmapsto Volume=Base\times Height

\\ \tt\longmapsto Height=\dfrac{Volume}{Base}

\\ \tt\longmapsto Height=\dfrac{2.9km^3}{339km^2}

\\ \tt\longmapsto Height=0.00079km

\\ \tt\longmapsto Height=7.9m

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Tanya and Reece each walked 4 miles on Monday. Reese also walked 4 miles on Tuesday and 4 miles on Wednesday . How many miles di
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Answer:

12 miles

Step-by-step explanation:

monday=4 miles

tuesday=4 miles

wednesday= 4 miles

4+4+4=12

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The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th
Fantom [35]

Answer:

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C

Step-by-step explanation:

To find:

∫6x^5(x^6-2)\,dx

Solution:

Method of substitution:

Let x^6-2=t

Differentiate both sides with respect to t

6x^5\,dx=dt

[use (x^n)'=nx^{n-1}]

So,

∫6x^5(x^6-2)\,dx = ∫ t\,dt = \frac{t^2}{2}+C_1 where C_1 is a variable.

(Use ∫t^n\,dt=\frac{t^{n+1} }{n+1} )

Put t=x^6-2

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1

Use (a-b)^2=a^2+b^2-2ab

So,

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C

where C=2+C_1

Without using substitution:

∫6x^5(x^6-2)\,dx = ∫6x^{11}-12x^5\,dx = \frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C

So, same answer is obtained in both the cases.

7 0
2 years ago
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