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Lelu [443]
3 years ago
10

List two additional populations (other than those listed in the lab) for which

Biology
1 answer:
omeli [17]3 years ago
6 0

Indirect methods like mark and recapture become a strong tool to estimate population size or density in species on which it is impossible to apply a direct methods. <em>Because of their biological and ecological characteristics, the Gypsy moth and the Green lizard populations are good examples  for which  mark and recapture would work well.</em>

<em>------------------------------------------------------</em>

There are different methods to study population density. There are direct methods and indirect methods. Among these last ones, we might find the Mark-Recapture technique.

The Mark-Recapture technique assumes that

  • <em>the population is closed during the sampling season, there is no mortality nor natality, </em>
  • <em>marks in the individual last the whole sampling season, and they do not affect the marked individual or their behavior. </em>
  • <em>marked individuals are randomly distributed in the population, and </em>
  • <em>all the individuals have the same probability of being sampled.</em>

The method consists of capturing a sample of individuals belonging to the population under study. After capturing the individuals, the researcher marks and releases them again. The third step is to sample again: The researcher captures new individuals and counts how many of them are marked. These marked individuals belong to the first sample.

Indirect methods like this become a strong tool to estimate population size or density in species on which it is impossible to apply a direct method such as <em>counting individuals</em>.

For instance, if we need to estimate insects population density (<u><em>Gypsy moth population</em></u>) or reptiles population density (<u><em>Green lizard population</em></u>) because of their biological and ecological characteristics, the best way of doing it is by applying indirect methods. <em>These species characterize as small-sized, fast to escape, they can hide in small inaccessible places, they have nocturnal habits, their reproductive rate is too high, and their distribution rate is wide. </em>Among many other characteristics, their population density can not be estimated by direct methods. Mark-Recapture technique is the most suitable one.

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Related link: brainly.com/question/10646744?referrer=searchResults

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<u>ANSWER:</u>

The correct order is-  Zygote, Blastula, Gastrula, Fetus.

<u>EXPLANATION:</u>

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Let Y = yellow and y = green, and R = round and r = wrinkled. You cross YYRR peas with yyrr peas. All of the F1 individuals are
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Answer:

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Given that the F2 cross produces offspring according to the expected 9:3:3:1 ratio.

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Let us break the dihybrid cross into individual monohybrid crosses.

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2/4 or 1/2 of the offspring are heterozygous for the trait.

Similarly, in Rr X Rr cross, 1/2 of the offspring are heterozygous for the trait.

Together, 1/2 * 1/2 = 1/4 of F2 plants are expected to be heterozygous for both traits.

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4. Which of the following conclusions about science is best supported by the text?
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In guinea pigs the allele for black fur (B) is dominant over the allele for brown fur (b), and the allele for short fur (F) is d
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Answer:

100%

Explanation:

This question involves two genes in guinea pigs; one coding for fur color and the other for fur length. The alleles of black fur (B) and short fur (F) is dominant over the alleles for brown fur (b) and long fur (f).

In a cross between two offsprings with genotypes: BBFF x bbff, the following gametes will be produced by each parent:

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bbff - bf, bf, bf, bf

Using these gametes in a punnet square (see attached image), one will notice that all of the offsprings will have the genotype: BbFf i.e all or 100% of the offsprings are heterozygous for both of the genes or traits.

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What might happen if a continent stops rifting apart?
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