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kramer
3 years ago
13

Find each angle. Separate your awnser with a comma. For an example 18, 72

Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0
(5x+7) + (8x-21) = 90
13x-14 = 90
13x= 104
X=8
The angle measurements are 47, and 43
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A pyramid has a regular hexagonal base with side links of four and a slant height of six. Find the total area of the pyramid
vova2212 [387]

Area of the Base = 6 * side^2 / 4 * tan (180/6)

Area of the Base = 6 * 16 / 4 * 0.57735

Area of the Base = 96 / 2.3094

Area of the Base = 41.5692387633


Area of 1 Face = 2 * 6 = 12

Area of 6 Faces = 72


Total Area = 41.5692387633 + 72

Total Area = 113.5692387633

7 0
4 years ago
Find the equation of the line specified. The slope is -7, and it passes through ( 5, -3).
Montano1993 [528]
The general equation of a line is
y= ax + b
where a is the slope
So a = -7
So y= -7x + b
But it passes through the point (5, -3)
Substitute the coordinates to calculate b:
So -3 = -7(5) + b
-3 = -35 + b
b= 35-3
b= 32
So the equation of the line of slope -7 and passing through the point (5, -3) is
y= -7x + 32
7 0
3 years ago
Read 2 more answers
Help please!!!!!!!!!​
devlian [24]

Answer:

YOU not smartYOU DONT KNOW THIS HA HA NOT HELPING YOU BOT.

Step-by-step explanation:

4 0
3 years ago
Given f(x)=x^2+4x+7 .
ivolga24 [154]
The correct answer for this question is A. 
3 0
3 years ago
MATH HELP PLEASE 50 POINTS:
Delicious77 [7]

Answer:

f(x)=-a(x+2)(2x-1)(x-3) where a>0.

To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.

Step-by-step explanation:

The real zeros are the result of setting each factor of the polynomial to zero. By reversing this process, we find:

  • zero -2 is factor (x+2)
  • zero 1/2 is factor (2x-1)
  • zero 3 is factor (x-3)

We write them together with an unknown leading coefficient a which is negative so -a.

f(x)=-a(x+2)(2x-1)(x-3) where a>0

The leading coefficient of a polynomial determines the direction of the graph's end behavior.

  • A positive leading coefficient has the end behavior point up when an even degree and point opposite directions when an odd degree with the left down and the right up.
  • A negative leading coefficient has the end behavior point down when an even degree and point opposite directions when an odd degree with the left up and the right down.
  • This graph has all odd multiplicity. The graph will cross through the x-axis each time at its real zeros.

To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.

4 0
3 years ago
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