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Zina [86]
3 years ago
5

Thirty percent (30%) of the bulbs in a large box are defective. If 12 bulbs are selected randomly from the box, calculate the pr

obability that exactly 6 are defective.​
Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0

The probability that exactly 6 are defective is 0.0792.

Given:

30% of the bulbs in a large box are defective.

If 12 bulbs are selected randomly from the box.

To find:

The probability that exactly 6 are defective.​

Solution:

Probability of defective bulbs is:

p=30\%

p=\dfrac{30}{100}

p=0.3

Probability of non-defective bulbs is:

q=1-p

q=1-0.3

q=0.7

The probability that exactly 6 are defective is:

P(x=r)=^nC_rp^rq^{n-r}

P(x=6)=^{12}C_6(0.3)^6(0.7)^{12-6}

P(x=6)=924(0.3)^6(0.7)^{6}

P(x=6)=0.0792478958

P(x=6)\approx 0.0792

Therefore, the probability that exactly 6 are defective is 0.0792.

Learn more:

brainly.com/question/12917164

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