How many ounces in a pound is 16 ounces.
first off, make sure you have a Unit Circle, if you don't do get one, you'll need it, you can find many online.
let's double up 67.5°, that way we can use the half-angle identity for the cosine of it, so hmmm twice 67.5 is simply 135°, keeping in mind that 135° is really 90° + 45°, and that whilst 135° is on the 2nd Quadrant and its cosine is negative 67.5° is on the 1st Quadrant where cosine is positive, so
![cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta) \\\\\\ cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos(135^o)\implies cos(90^o+45^o)\implies cos(90^o)cos(45^o)~~ - ~~sin(90^o)sin(45^o) \\\\\\ \left( 0 \right)\left( \cfrac{\sqrt{2}}{2} \right)~~ - ~~\left( 1\right)\left( \cfrac{\sqrt{2}}{2} \right)\implies -\cfrac{\sqrt{2}}{2} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=cos%28%5Calpha%20%2B%20%5Cbeta%29%3D%20cos%28%5Calpha%29cos%28%5Cbeta%29-%20sin%28%5Calpha%29sin%28%5Cbeta%29%20%5C%5C%5C%5C%5C%5C%20cos%5Cleft%28%5Ccfrac%7B%5Ctheta%7D%7B2%7D%5Cright%29%3D%5Cpm%20%5Csqrt%7B%5Ccfrac%7B1%2Bcos%28%5Ctheta%29%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20cos%28135%5Eo%29%5Cimplies%20cos%2890%5Eo%2B45%5Eo%29%5Cimplies%20cos%2890%5Eo%29cos%2845%5Eo%29~~%20-%20~~sin%2890%5Eo%29sin%2845%5Eo%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28%200%20%5Cright%29%5Cleft%28%20%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5Cright%29~~%20-%20~~%5Cleft%28%201%5Cright%29%5Cleft%28%20%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5Cright%29%5Cimplies%20-%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer: f(5) = 16
Step-by-step explanation:
f(n) = (2n + 3)2 – 2n
f(5) = ((2 x 5) + 3)2 – 2 x 5
f(5) = (10 + 3)2 – 10
f(5) = (13)2 – 10
f(5) = 26 – 10
f(5) = 16
Step-by-step explanation:
we use the law of sine :
sin(A)/a = sin(B)/b = sin(C)/c
with the related angles being opposite of the lines.
so, we have
sin(A)/1 = sin(A) = sin(90)/ sqrt(10) = 1/ sqrt(10) =
= 0.316227766...
cos²(A) + sin²(A) = 1
cos(A) = sqrt(1 - sin²(A)) = sqrt(1 - 0.1)) = sqrt(0.9) =
= 0.948683298...
tan(A) = sin(A)/cos(A) = 0.333333333...
cot(A) = 1/tan(A) = 3
sec(A) = 1/cos(A) = 1.054092553...
csc(A) = 1/sin(A) = 3.16227766...
Answer:
8182 kilometers
Step-by-step explanation:
A correct proportion to use is 22 over 5,000 = 36 over d
Cross multiply to get 22d = 5,000 x 36. Then, solve d. d = 8181.81.......so the approximate distance rounded to the nearest whole number from London to Beijing is 8182 kilometers.
Hope This Is Right.....
