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3 years ago

What is the difference between the mass of a solid and the mass of a liquid?

Mathematics

1 answer:

madreJ [45]3 years ago

8 0

Answer:

A solid is a form of matter characterized by a particular shape that also has volume. A liquid, on the other hand, has volume but no exact shape, taking the shape of its container. The molecules in solid matter are compressed as its molecules are closely bound together and can only vibrate.

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Write the sentence as an inequality

oee [108]

Answer:

X2+4<10

Step-by-step explanation:

7 0

3 years ago

HELP NOW IS THIS CORRECT

Arisa [49]

Yes this question is correct

4 0

4 years ago

An electrician sent Bonnie an invoice in the amount of 'a' dollars for 6 hours of work that was done on Saturday. The electricia

Mazyrski [523]

Answer:

(a-f)/6 = r

Step-by-step explanation:

The total Bonnie must pay is the weekend fee plus the hourly rate times the hours worked

Cost = weekend fee * hourly rate* hours

hours = 6

weekend fee =f

hourly rate = r

Cost = a dollars

Substituting in what we know

a = f+ 6r

We want to solve for r

Subtract f from each side

a-f =f-f +6r

a-f = 6r

Divide each side by 6

(a-f)/6 = 6r/6

(a-f)/6 = r

4 0

3 years ago

Without using trignometery tables find value of , cos70/sin20+cos57.cosec33 - 2cos60

Helen [10]

Here is some thoughts on this:

cos 57 = sin (90-57) = sin 33

so cos 57 . cosec 33 = cos 57 / sin 33 = sin 33 / sin33 = 1

2 cos 60 = 2 * 1/2 = 1

so the last 2 parts work out to 0

now we have to find cos 70 / sin 20

sin 20 = cos 70 so this comes to 1

so finally the answer is 1

4 0

3 years ago

A rectangular public park has an area of 3,600 square feet. It is surrounded on three sides by a chain link fence. If the entire

Dafna11 [192]

Answer:

If length of the field is 30 ft, then width is 120 ft.

If the length of the field is 60 ft, then width is 60 ft.

Step-by-step explanation:

Let us assume the length of the rectangular park = L ft

Let us assume the breadth of the rectangular park = B ft

Now, AREA of the given park = L x B

⇒ L x B = 3,600 sq ft ... (1)

Also, the perimeter of three sides = 180 ft

⇒ 2 L + B = 180 ..... (2)

Now, from (1) and (2), we get:

L x B = 3,600

2 L + B = 180 ⇒ B = 180 - 2 L

Substitute this in(1) , we get:

L x B = 3,600 ⇒ L x (180 - 2 L) = 3600

$\implies 180 L - 2L^2 = 3600\\\implies L^2 -90L + 1800 = 0\\\implies (L-30)(L-60)= 0$

⇒ L = 30 or L = 60

So, if L = 30 ft , then B = 180 - 2L = 180 - 60 = 120 ft

So, if L = 60 ft , then B = 180 - 2L = 180 - 120 = 60 ft

So, if length of the field is 30 ft, then width is 120 ft.

And if the length of the field is 60 ft, then width is 60 ft.

4 0

3 years ago