Answer:
Check the ecplanation
Step-by-step explanation:
A set of three vectors in 
represents a matrix of 3 column vectors, and each vector containing 4 entries (that is, a matrix of 4 rows, and 3 columns).
Let A be that 4x 3 matrix. The columns of A span 
. if and only if A has a pivot position in each row. So, there are at most 3 pivot positions in the matrix A, but the number of rows is 4, therefore, there exist at least one row not having a pivot position. If A does not have a pivot position in at least one row, then the columns of A do not span . It implies that the set of 3 vectors of A does not span all of .
In general, the set of n vectors in represents a matrix of in rows, and n columns (an in x matrix). So, there are at most n pivot positions in the matrix A, but n is less than the number of rows. In therefore, there exist at least one row that does not contain a pivot position.
And, hence the set of n vectors of A does not span all of . for n < m
Answer:
C
Step-by-step explanation:
621,864
Since the 4 is a smaller digit than a 5, the 6 in the tens place would stay the same while the 4 would become a 0.
B
The equation of a line in ' point- slope form ' is
y - b = m( x - a )
where m is the slope and (a, b ) a point on the line
here m = 
and (a, b ) = (3, 2 )
y - 2 = ( x - 3 ) → in point- slope form
The answer is 2.99 explanation is that I used my calculator lol
