Equation: (Not sure if it's the right order...)
468 = 40x + 18(x - 3)
The fee Micheal charges each suscriber is $6
Work:
468 = 40x + 18(x - 3)
468 = 40x + 18x - 54
Mutilpy 18 & x and 18 & 3
468 = 58x - 54
Add 40x amd 18x
468 + 54 = 58x - 54
Add 54 to 468 to have -54 gone in 58x - 54
522 divide by 58 is 9
x = 9
9 - 3 = 6
Ok... we'll do the same here, elimination
g = carbs in one glass of milk
b = carbs in a snack bar
in this, we can simply multiply by -2 at the bottom to get a -4g, and thus "eliminate" the g-variable
Step-by-step explanation:
let the angle in 3rd quadrant be X
x+2=180
Answer:
h≤-19/6
Step-by-step explanation:
10 2/3 + 2h ≤ 4 1/3?
-10 2/3 -10 2/3
2h/-19/3≤ -19/3/-19/3
h≤-19/6
Step-by-step explanation:
15% acid solution to get (10+x) liters of 20% acid solution:

That equation is simply solved using basic algebra; you might want to first multiply the whole equation by 100 to get rid of the decimals.
Here is what I think is a faster and easier way to solve mixture problems like this, without the decimals and the formal algebra.
(1) The target percentage of 20% is 5% away from 15% (20-15 = 5) and 16% away from 36% (36-20 = 16).
(2) The ratio of those differences (5:16) is the ratio in which the two ingredients must be mixed; common sense says the larger portion needs to be the 15% solution, since 20% is closer to 15% than to 36%. So we need 16 parts of 15% acid solution to 5 parts of the 36% acid solution.
(3) Since we know there are 10 liters of the 36% acid solution, we solve the problem with a simple proportion: 10 liters of 36% acid solution and x liters of 15% acid solution need to be mixed in the ratio 5:16:



ANSWER: You need 32 liters of 15% acid solution to be mixed with the 10 liters of 36% acid solution to make a 20% acid solution.
All the words of explanation make it seem like more work than the traditional algebraic solution method. But without the words, you can see that the calculations are quick and easy:
36-20 = 16; 20-15 = 5
5:16 = 10:x --> x = 2*16 = 32