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gtnhenbr [62]
3 years ago
11

what is the slope of the line that passes through the points (4,4) and (10,7)? write your answer in simplest form

Mathematics
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:

\boxed {\boxed {\sf m= \frac{1}{2}}}

Step-by-step explanation:

We are asked to find the slope of a line that passes through 2 points. The slope tells us the steepness and direction of a line. It is calculated using the following formula:

m= \frac {y_2-y_1}{x_2-x_1}

In this formula, (x₁ , y₁) and (x₂, y₂) are the points the line passes through. The points are (4,4) and (10,7). If we match the value and the corresponding variable we see that:

  • x₁ = 4
  • y₁= 4
  • x₂ = 10
  • y₂= 7

Substitute the values into the formula.

m= \frac{7-4}{10-4}

Solve the numerator.

  • 7-4=3

m= \frac{3}{10-4}

Solve the denominator.

  • 10-4= 6

m= \frac{3}{6}

This fraction can be reduced. Both the numerator and denominator can be divided by 3.

m= \frac{3/3}{6/3}

m= \frac{1}{2}

The slope of the line that passes through (4,4) and (10,7) is <u>1/2.</u>

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Sholpan [36]

Answer:

Step-by-step explanation: what triangle?

4 0
2 years ago
A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter
faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.

So the amount of chlorine in the tank changes according to

\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):

\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0

\dfrac1{(200-3t)^{5/3}}\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{(200-3t)^{8/3}}=0

\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0

\dfrac{c(t)}{(200-3t)^{5/3}}=C

c(t)=C(200-3t)^{5/3}

There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

20=C(200)^{5/3}\implies C=\dfrac1{200\cdot5^{1/3}}

\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}

7 0
2 years ago
HELP ME PLEASE
Mashutka [201]

Answer:

9 + \frac{n}{3} - 6 = 7

Step-by-step explanation:

Given

9 + \frac{n}{3} - 6

Required

Evaluate when n = 12

Substitute 12 for n in 9 + \frac{n}{3} - 6

9 + \frac{n}{3} - 6 = 9 + \frac{12}{3} - 6

Simplify the fraction

9 + \frac{n}{3} - 6 = 9 + 4 - 6

9 + \frac{n}{3} - 6 = 7

4 0
3 years ago
PLEASE HELP ME ASAP! Please show your work.
Marysya12 [62]
Its 18....................................


6 0
3 years ago
Wha is 3x+3y=-9 in standard to slope intercept form simplified, thank you!
Alona [7]

Answer

Step-by-step explanation:

The answer would be y=-x-3. 3x+3y=-9 is in standard form and you want it to be in y=mx=b form (slope-int) so subtract 3x by both sides. Now, you have 3y=-3x-9. Divide 3 to both sides, now you will get y=-x-3.

6 0
3 years ago
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