Answer:
Bet
Step-by-step explanation:
It’s a simple one to write. There are many trios of integers (x,y,z) that satisfy x²+y²=z². These are known as the Pythagorean Triples, like (3,4,5) and (5,12,13). Now, do any trios (x,y,z) satisfy x³+y³=z³? The answer is no, and that’s Fermat’s Last Theorem.
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
For the first one at the top it’s 300 and 575 then going down it’s 17.21, 63.33, and then 184.68
Answer:
-6
Step-by-step explanation:
is -6
Answer:
7/10
Step-by-step explanation:
3/10+2/5
You have to make like denominators
So you multiply 2/5 by 2 since 1/ is the common denominator.
Then you add them
Hope this helped
Good afternoon,
x= first odd integer
x+2 = second odd integer
x+4= third intenger
The sum of the trhree integer is 195, so:
x + (x+2) + (x+4) = 195
3x = 195 - 4 - 2
3x=189
x= 63
Then the Answer is: 63, 65 and 67
