3 years ago

11²-5+4(7)/(4)(3) Help!

Mathematics

1 answer:

siniylev [52]3 years ago

6 0

Answer: 137

Step-by-step explanation: 11^2−5+(4)(7)/4(3)

121−5+(4)(7)/4(3)

116+(4)(7)/4(3)

116+(28/4)(3)

116+(7)(3)

116+21

137

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Let N+2 denote the natural numbers greater than or equal to 2. Let mRn if gcd(m, n) > 1. The binary relation R on N2 is

GaryK [48]

Answer:

a) Reflexive, Symmetric, Not Transitive

Step-by-step explanation:

Given $a\in N+2$ we have that $a\ge 2$ and then $\gcd(a,a)=a\ge 2$ thus the binary relation is reflexive. To show that is symmetric note that for $a,b\in N+2$ we have $\gcd(a,b)=\gcd(b,a)$ which implies the symmetric. In fact, the relation is <u>not</u> transitive, for example note that $\gcd(7,7^2)=7$ and $\gcd(5^2,5)$ but $\gcd(7,5)=1$ .