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dimulka [17.4K]
3 years ago
5

Can 25 go into 33? please help me out!

Mathematics
1 answer:
AlexFokin [52]3 years ago
6 0
25 will go into 33 once, with a remainder of eight.
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Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

6 0
3 years ago
A restaurant offers a combo special with 3 different sandwiches, 2 different salads, and 5 different drinks. From how many diffe
m_a_m_a [10]

Answer:

30 ways

Step-by-step explanation:

Given the following information:

  • 3 different sandwiches
  • 2 different salads
  • 5 different drinks

Let assume that the combo contains:  1 sandwich, 1 salad, and 1 drink

Hence, we have:

  • The total possible ways of choosing sandwiches she can choose is: 3
  • The total possible ways of choosing salads she can choose is: 2
  • The total possible ways of choosing drinks she can choose is: 5

=> Total ways = 3*5*2 = 30 ways or there are 30 different combos Keisha can choose

Hope it will find you well.

5 0
3 years ago
1. ΔABC and ΔDEF are similar = Given
deff fn [24]
I think the answer is d. The slope of AC=Slope of DF.

Hope this helped☺☺
3 0
3 years ago
Read 2 more answers
If a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11, what is the
Debora [2.8K]

Answer:

2x+4

Step-by-step explanation:

Given that a is the average (arithmetic mean) of 4x and 7, b is the average of 5x and 6, and c is the average of 3x and 11

By definition of arithmetic mean,

we have a=\frac{4x+7}{2} \\b=\frac{5x+6}{2} \\c=\frac{3x+11}{2}

Let us calculate sum of a,b,c in terms of x

a+b+c = \frac{4x+7+5x+6+3x+11}{2} \\=6x+12

Average = sum/3 = \frac{6x+12}{3} =2x+4

7 0
3 years ago
What value of n makes the equation true? (2x^9y^n)(4x^2y^10)=8x^11y^20
Komok [63]
Hi there! The answer is n = 10.

(2 {x}^{9}  {y}^{n} )(4 {x}^{2}  {y}^{10} ) = 8 {x}^{11}  {y}^{20}

As you see at the powers of x, we need to add the exponents of the power we when multiply them.
{x}^{9}  \times  {x}^{2}  =  {x}^{9 + 2}  = x {}^{11}

The powers of y work the same way.
{y}^{n}  \times  {y}^{10}  =  {y}^{n + 10}  =  {y}^{20}

Hence, n = 10, since
{y}^{10 + 10}  =  {y}^{20}
8 0
3 years ago
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