Step-by-step explanation:
here's the solution,
in the given figure , sum of all angles formed with O measures 360°
because, it forms a complete angle
so,
=》mPOQ + mQOR + mROS + mSOT + mTOP = 360°
=》mPOQ + mQOR + mROS + mSOT + mTOP = (90° × 4)
=》mPOQ + mQOR + mROS + mSOT + mTOP = 4 × right angle
(cuz.. right angle = 90°)
6 i believe but im not sure
In the attachement, there is what I came up with so far. I think that finding 'a' is non-trivial, if possible at all.
- the area of a circle
- the area of a circular segment
Things we know:
Six total pots = # of 10" + # of 8"
$78 total = cost of 10" + cost of 8"
So:
6 = x +y
and
78 = x*(cost of x) + y * (cost of y)
78 = x*12 + y*15
We need:
x+y=6 AND 12x+15y=78
So our answer can only be B.
C3-36
the 3 is “c3” is an exponent btw!
