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Fittoniya [83]
3 years ago
9

If Mary has 12 more mangoes than Jason and Jason has y mangoes how many has Mary?​

Mathematics
1 answer:
xeze [42]3 years ago
3 0

Answer:

y+12=m

Step-by-step explanation:

m (marys mangos)

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2x=-y in standard form
IgorC [24]

Answer:

y=-2x

Step-by-step explanation:

4 0
3 years ago
9. Write an equation of a parabola that opens to the right, has a vertex at the origin, and a focus at (7,0).
Nookie1986 [14]

Answer:

x = \frac{1}{28} y^{2}

Step-by-step explanation:

parabola equation with vertex (0 , 0) and focus length |f| = 7

4*f*(x - h) = (y - k)²

4*7*(x-0)=(y-0)²

28x = y²

x = \frac{1}{28} y^{2}

6 0
3 years ago
11.1 billion dollars is spent on line over the Thanksgiving weekend. An amount that is equal to 1.05% of that is given to charit
Yuki888 [10]
11100000000 x 1.05%
=11100000000 x 0.0105
=$116550000

Hope I can help u
8 0
3 years ago
Read 2 more answers
Gill rolls a number cube 78 times. How many times can he expect to roll an odd number greater than 1?
bekas [8.4K]
Im assuming its just a regular number cube with 6 numbers 
there are only 2 odd numbers above 1 ( 3 and 5) 

so the ratio is 2/6 

you want to know how manny times (x) will you roll those numbers out of 78 roll 
the ratio is x/78 

multiply 

(2/6) = (x/78) 

cross multply to give you 6x= 156 and divide by 6 

<span>to give you x = 26 


</span>
3 0
3 years ago
Read 2 more answers
A charter fishing company buys a new boat for $224,000 and assumes that it will have a trade-in value of $115,200 after 16 years
vodka [1.7K]

First, according to the information, we build a linear model, and then, the model is used to find the information asked.

a) The linear model is:

V(t) = 224000 - 6800t

b) The depreciated value of the boat after 10 years is of $156,000.

c) The depreciated value falls below $100,000 after 18.24 years.

d) The sketch is given at the end of the answer.

Item a:

  • The initial value is of $224,000, thus, the y-intercept of the linear function is of b = 224000.
  • The value decayed to $115,200 in 16 years, thus, the slope of the linear function is:

m = \frac{115200 - 224000}{16} = -6800

Then, the linear model is:

V(t) = 224000 - 6800t

Item b:

The value after 10 years is V(10), so:

V(10) = 224000 - 6800(10) = 156000

Then, the depreciated value of the boat after 10 years is of $156,000.

Item c:

This is t for which: V(t) = 100000. So

V(t) = 224000 - 6800t

100000 = 224000 - 6800t

6800t = 224000 - 100000

6800t = 124000

t = \frac{124000}{6800}

t = 18.24

The depreciated value falls below $100,000 after 18.24 years.

Item d:

The sketch is appended at the end of this answer.

A similar problem is given at brainly.com/question/24978772

3 0
3 years ago
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