The last one because the base is a square
Answer:
0
Step-by-step explanation:
Anything times 0 is always 0.
The subtraction gives -7x^2( x + 1) - 3
<h3>What are algebraic expressions?</h3>
Algebraic expressions are expressions are expressions that are made up of factors, terms, variables and constants.
They also consist of arithmetic operations.
We have to subtract (6x^3 − x^2 + 8x + 5) from (−x^3 − 9x^2 + 2)
It is written as;
(−x^3 − 9x^2 + 2) - (6x^3 − x^2 + 8x + 5)
−x^3 − 9x^2 + 2 - 6x^3 + x^2 - 8x - 5
collect like terms
-x^3 - 6x^3 - 9x^2 + x^2 + 2 - 5
Add like terms
-7x^3 - 7x^2 - 3
To simply further
-7x^2( x + 1) - 3
Thus, the subtraction gives -7x^2( x + 1) - 3
Learn more about algebraic expressions here:
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Answer: 90,000
Step-by-step explanation:
From the question, we are informed that in a local town, 54,000 families have incomes less than $25,000 per year. We are further told that this number of families is 60% of the families that had this income level 12 years ago.
To calculate the number of families who had incomes less than 25,000 per year 12 years ago goes thus:
Let the the number of families who had incomes less than 25,000 per year 12 years ago be represented by x.
Since we are told that this number of families is 60% of the families that had this income level 12 years ago. This means that:
60% of x = 54,000
60/100 × x = 54,000
0.6 × x = 54,000
0.6x = 54,000
Divide by 0.6
0.6x/0.6 = 54000/0.6
x = 90,000
The number of families who had incomes less than 25,000 per year 12 years ago was 90,000.