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2 years ago

Please answer Find the product.(7m^2-3m-7)(m^2-7m-6)

Mathematics

1 answer:

densk [106]2 years ago

6 0

Step-by-step explanation:

(7m²-3m-7)(m²-7m-6) =

7m⁴-49m³-42m²-3m³+21m²+18m

-7m²+49m+42

= 7m⁴-52m³-28m²+67m+42

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dangina [55]

The answer is C) m∠1 + m∠2 = 90

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Basically you know than ∠3 is 90° ... And a straight line is 180° .. So technically we can just find out 180-90 is 90(the other angle 1 + 2).

To get 90° we'll add ∠1 and ∠2 in other ways, like technical thinking-

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In other words you can say m∠1 + m∠2 = 90

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3 years ago

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3 years ago

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3 years ago

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3 years ago

The 3 by 3 grid below shows nine 1 cm × 1 cm squares and uses 24 cm of wire. What length of wire is required for a similar 20 by

Nady [450]

Answer:

840

Step-by-step explanation:

Hi there!

Usually, this kind of problem asks us the perimeter rather than the area. But when talking on this grid on how many cms are necessary to construct one made up of 9 squares 1cm x1 cm. We need to check one thing: Some line segments will be used twice. So this is not a classical perimeter question.

1) So we either manually and carefully count it avoiding not doing it twice the same common line segments.

Or.

2) By just applying an algorithm, Where n is the <em>nxn</em> grid

$n(n+1)+n(n+1)=Length \:of \:the \:wire$

So, for the 20x20 grid

$20(20+1)+20(20+1)=length\\\\20(21)+20(21)=length\\length=840 cm$

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3 years ago

Please answer Find the product.(7m^2-3m-7)(m^2-7m-6)​

Please answer Find the product.(7m^2-3m-7)(m^2-7m-6)