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max2010maxim [7]
3 years ago
6

F(x) = x² + 3x – 4 find the difference quotient hurry!!!

Mathematics
1 answer:
EleoNora [17]3 years ago
5 0

Answer:

2x + h + 3

Step-by-step explanation:

2x + h + 3

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Which is greater? -1 17/20 or -1 8/10PLSSS HELP ASAPplsss show work aswell
wel
-1 17/20 and -1 8/10 can be compared easily if we give them common denominators. If we multiply the second fraction by 2, both fractions will have a denominator of 20.

8 * 2 = 16
10 * 2 = 20
New fraction: 16/20

-1 17/20 vs. - 1 16/20

-1 16/20 (-1 8/10) is greater. (For negative numbers, you can tell which one is greater by determining which one is closest to zero.)
6 0
2 years ago
The train will take one hour, then the bus will take two and a half hours. I need to allow half an hour to change between them.
ser-zykov [4K]

Answer:

Step-by-step explanation:

answer: 4 hours

8 0
2 years ago
Multiply 5⋅2/3.<br> Write your answer as a mixed number. <br> 10/3 <br> 2 /13 <br> 7/3 <br> 3 1/3
Oksana_A [137]

Answer: Heyaa!

Your Answer Is... 10/3

Step-by-step explanation:

<u>Simplify the expression.</u>

Hopefully this helps <em>you !</em>

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<em>- Matthew ~~</em> ( have an amazing day)

8 0
2 years ago
12) A radio transmission tower is 170 feet tall. How long should a guy wire be if it is to be attached 15 feet from the top and
ser-zykov [4K]

The length of guy wire needed to make an angle of 30° with the ground is 310 feet. The angle between the end of the shadow and the vertical side of the building is 23°

<h3>What is trigonometric ratio?</h3>

Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.

a) Let l represent the length of the guy wire.

sin(30) = (170 - 15) / l

l = 310 feet

b) Let Ф represent the angle, hence:

tanФ = 100/230

Ф = 23°

The length of guy wire needed to make an angle of 30° with the ground is 310 feet. The angle between the end of the shadow and the vertical side of the building is 23°

Find out more on trigonometric ratio at: brainly.com/question/24349828

6 0
1 year ago
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
yuradex [85]

Answer:

0 < t < 5 is the required interval for the differential equation (t - 5)y' + (ln t)y = 6t to have a solution.

Step-by-step explanation:

Given the differential equation

(t - 5)y' + (ln t)y = 6t

and the condition y(1) = 6

We can rewrite the differential equation by dividing it by (t - 5) as

y' + [(ln t)/(t - 5)]y = 6t/(t - 5)

(ln t)/(t - 5) is continuous on the interval (0, 5) and (5, +infinity).

6t/(t - 5) is continuous on (-infinity, 5) and (5, +infinity)

We see that for these expressions, we have continuity at the intervals (0, 5) and (5, +infinity).

But the initial condition is y = 6, when t = 1.

The solution to differential equation is certain to exist at (0, 5)

Which implies that

0 < t < 5

is the required interval.

3 0
3 years ago
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