Answer:
<em>l</em> = 1 5/16
w = 1/16
A = 21/16 x 1/16 = 21/256
Step-by-step explanation:
Perimeter = 11/4
<em>l</em> = length
w = <em>l</em> - 5/4
2<em>l</em> + 2(<em>l</em> - 5/4) = 11/4
2<em>l</em> + 2<em>l</em> - -5/2 = 1/4
multiply each side by 4
8<em>l</em> + 8<em>l </em>- 10 = 11<em> </em>
16<em>l</em> = 21
<em>l</em> = 21/16 or 1 5/16
width = 21/16 - 20/16 = 1/16
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Answer:
Its just 16.
Step-by-step explanation: