3 years ago

Help!!! me please!!!

Mathematics

1 answer:

stepan [7]3 years ago

7 0

Answer:

Step-by-step explanation:

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Suppose 40% of the students in a university are baseball players. If a sample of 781 students is selected, what is the probabili

3241004551 [841]

Answer:

$P(p>0.43) = 0.0436$

Step-by-step explanation:

Given

$p = 40\%$ -- proportion of baseball players

$n = 781$ --- selected sample

Required

Determine P(p>43%)

First, calculate the z score using:

$Z = \frac{\^{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

This gives:

$Z = \frac{48\%-40\%}{\sqrt{\frac{40\% *(1 - 40\%)}{781}}}$

Convert % to decimal

$Z = \frac{0.43-0.40}{\sqrt{\frac{0.40 *(1 - 0.40)}{781}}}$

$Z = \frac{0.43-0.40}{\sqrt{\frac{0.40 *0.60}{781}}}$

$Z = \frac{0.43-0.40}{\sqrt{\frac{0.24}{781}}}$

$Z = \frac{0.03}{\sqrt{0.00030729833}}$

$Z = \frac{0.03}{0.01752992669}$

$Z = 1.71$

So:

$P(p>0.43) = P(Z>1.71)$

$P(p>0.43) = 1 - P(Z$

$P(p>0.43) = 1 - 0.9564$

$P(p>0.43) = 0.0436$

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3 years ago

Is this correct????????

Pavel [41]

Answer:

i dont see photo

Step-by-step explanation:

i don't no..

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3 years ago