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dezoksy [38]
3 years ago
12

Find the location of K

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

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A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the
nydimaria [60]

Answer:

Step-by-step explanation:

As you can see, this is a quadratic equation and if you were to graph this you would see that it is a parabola that opens down because of the negative leading coefficient (-34). The maximum profit would be at the vertex, of the graph. Therefore, we need to find the value of "y" when "x" is the line of symmetry. We find this by  x=-b/(2a) where a = -34 and b = 1542:

x=-1542/(2)(-34)

x=-152/-68

x=152/68  

We put this value of "x" into the original formula to find out the value of "y":

y=-34x^2+1542x-10037

y=(-34)(1542/68)^2+1542(1542/68)-10037

y= -17483.5588235 + 34967.1176471 -10037

y=7446.5588236

Therefore, the maximum profit would be $7446.56.

Hope this helps!

PLS MARK BRAINLIEST THIS TOOK A LOT OF TIME

7 0
3 years ago
Which table represents a function that does not have a constant rate of change ?
EleoNora [17]

Answer:

I believe D.

Step-by-step explanation:

All the other tables increase at a stady rate but D doesn't.

4 0
3 years ago
Read 2 more answers
What is the quotient? 1462 divided 58 Enter your answer as a mixed number in the simplest form
stepan [7]
The answer would be 25.2or 126/5
8 0
3 years ago
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I do no understand this
vovangra [49]

The equation of a line for the given slope is y=\frac{1}{2} x+1.

Solution:

Given data:

Slope (m) = \frac{1}{2}

Point = (–2, 0)

x_1=-2, y_1=0

To find the equation of the given line in the point-slope form:

<u>Point-slope formula:</u>

y-y_1=m(x-x_1)

Substitute the given values in the formula.

$y-0=\frac{1}{2} (x-(-2))

$y=\frac{1}{2} (x+2)

$y=\frac{1}{2} x+\frac{2}{2}

$y=\frac{1}{2} x+1

The equation of a line for the given slope is y=\frac{1}{2} x+1.

5 0
3 years ago
Choose the correct response ​
Aliun [14]

Answer:

74 hope this works if not I'm sorry

6 0
3 years ago
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