Answer:
162 feet²
Explanation:
One length of a rectangular garden lies along a patio wall. However, the rest of the garden is enclosed by 36 feet of fencing. If the length of the garden is twice its width, what is the area of the garden?
Solution:
Let x represent the length of the garden and y represent the width of the garden. Since the length of the garden is twice its width, hence:
x = 2y
Since 36 feet of fencing was used to enclose the rest of the building:
x + y + y = 36
x + 2y = 36
Substitute x = 2y:
2y + 2y = 36
4y = 36
y = 36 / 4
y = 9 feet
Substitute y = 9 to find x:
x = 2y = 2(9) = 18 feet
Therefore the length of the fence is 18 feet and the width is 9 feet.
The area of the garden = length * width = 18 feet * 9 feet = 162 feet²
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The change was responsible for the election of a significant number of African American and Hispanic council members this is the effect of Dallas shifting from an at large to a single member district system in 1991. Dallas is a city in the United States state of Texas.