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ratelena [41]
3 years ago
11

Please someone help me

Mathematics
2 answers:
Vsevolod [243]3 years ago
5 0

Answer:

( - 12  \div 3) \times ( - 8 +   ({ - 4})^{2}  - 6) + 2

= ( - 4) \times ( - 8 + 16 - 6) + 2

= ( - 4) \times (2) + 2

=  - 8 + 2

=  - 6

saul85 [17]3 years ago
4 0

Step-by-step explanation:

( - 12 \div 3) \times ( - 8 +  {( - 4)}^{2}  + 2 \\  =  - 4 \times ( - 8 + 16 - 6) + 2 \\  =  - 4 \times ( - 8 + 10) + 2 \\  =  - 4 \times 2 + 2 \\  =  - 8 + 2 \\  =  - 6 \\ thank \: you

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In the figure below, mZ1=(x +48) and m2 2=2xº.<br> Find the angle measures.
NARA [144]
Since m < 1 and m < 2 are complementary angles wherein the measure of their angles add up to 90°, we can establish the following equation:

m < 1 + m < 2 = 90°
x° + 48° + 2x° = 90°

Combine like terms:
48° + 3x° = 90°

Subtract 48° from both sides:

48° - 48° + 3x° = 90° - 48°

3x = 42°

Divide both sides by 3 to solve for x:

3x/3 = 42/3

x = 14°

Plug in the value of x into the equation to fins m< 1 and m < 2:

m < 1 + m < 2 = 90°
(14° + 48°) + 2(14)° = 90°
62° + 28° = 90°

90° = 90° (True statement)

Therefore:

m < 1 = 62°
m < 2 = 28°
6 0
3 years ago
Which pair of angles are alternate exterior angles ?
Citrus2011 [14]

8 and 1 are alternate exterior angles.

8 0
3 years ago
Read 2 more answers
Which of the following statements is true
Tresset [83]
Hello There!

The first statement is incorrect as congruent angles have the same measure but it doesn't have to 45°. It can be any value.
The second one is also incorrect. Congruent angles have the same measure but don't always total to 180° (which is what supplementary means). It would only be true if they are congruent right angles.
The third one is also incorrect as they don't always total to 90° either (Which is what complementary means). 
The fourth one is correct, this is because congruent angles are simply angles with the same measure.

In short, you're answer is 4. Congruent angles always have the same measure. 


Hope This Helps You!
Good Luck :) 
6 0
3 years ago
Koran is spending $12 on games and rides at another carnival, where a game costs $0.25 and a ride costs $1.
Vlad [161]

Answer:

0.25x+y=12

Step-by-step explanation:

Let

y ----> the number of rides

x ---> the number of games

we know that

The number of rides multiplied by  $1 plus the number of games multiplied by $0.25 must be equal to $12 (the dollar amount Koran is spending)

so

The equation that represent this situation is

0.25x+y=12

5 0
3 years ago
Here are the endpoints of the segments BC, FG, and JK.<br> B, −67
yulyashka [42]

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

4 0
2 years ago
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