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EleoNora [17]
3 years ago
10

What is the solution to the equation –6x + 9 = 4x + 14?

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0

Answer:

-0.5

Step-by-step explanation:

work shown in image attached

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If x=73, what does 4x+3 equal?
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4(73)+3
273+3
276
 Because you have to subsititue 73 for x. So you have to multiply 73 by 4 then what you get out of that you have to add it by 3.

5 0
4 years ago
Is the ordered pair (3.2) a solution to the equation 5x+2y=11 show work out
EleoNora [17]
No, the coordinates doesn’t make the equation a true statement, therefore it can’t be a solution.

4 0
3 years ago
Find the midpoint of the line segment with endpoints P<br> P. ( 5 ) and P2 ( 13 )
kipiarov [429]

Answer:

9

Step-by-step explanation:

13 - 5 = 8

8 / 2 = 4

13 - 4 = 9

8 0
3 years ago
Selma had 2 L of bottle of water. She drank 450 mL. How much water was left, in milliliters?
Basile [38]

Answer:

The amount of water left is 1550 litres

7 0
3 years ago
Here's the data (sorted) of the ages of 91 women who won the Oscar for Best Actress in a Leading Role:
Andreyy89

Answer:

B. 21, 28, 33, 41, 81

Step-by-step explanation:

Data : 21, 22, 22, 24, 24, 24, 24, 25, 26, 26, 26, 26, 26, 26, 26, 26, 26, 27, 27, 27, 27, 28, 28, 28, 28, 29, 29, 29, 29, 29, 30, 30, 30, 30, 30, 30, 31, 31, 31, 32, 32, 33, 33, 33, 33, 33, 33, 33, 34, 34, 34, 34, 34, 35, 35, 35, 35, 35, 37, 37, 37, 37, 38, 38, 38, 39, 39, 39, 41, 41, 41, 41, 42, 42, 44, 45, 45, 45, 47, 49, 49, 54, 60, 60, 61, 61, 61, 62, 62, 74, 81

Five number summary includes :

1. Minimum vale

2. First Quartile

3. Median : mid value of the given data is 46th term = 33

4.Third Quartile

5.Maximum value

Solution :

1. Minimum vale : smallest value of data = 21

2. First Quartile: median of the data (first number to the actual median) i.e. from 1st term to 46th term

Median for even number of terms :  \frac{\frac{n}{2}th+(\frac{n}{2}+1)th}{2}

n = 46

so, median =  \frac{\frac{46}{2}th+(\frac{46}{2}+1)th}{2}

                    = \frac{23th+24th}{2}

                    = \frac{28+28}{2}

                   = \frac{56}{2}

                     = 28

Thus first quartile = 28                

3. Median : mid value of the given data(ages of 91 women) is 46th term = 33

4.Third Quartile :median of the data (46th number[actual median] to the 91th)

Median for even number of terms :  \frac{\frac{n}{2}th+(\frac{n}{2}+1)th}{2}

n = 46

so, median =  \frac{\frac{46}{2}th+(\frac{46}{2}+1)th}{2}

                    = \frac{23th+24th}{2}

                    = \frac{41+41}{2}

                   = \frac{82}{2}

                     = 41

Thus third quartile = 41

5.Maximum value : highest value of data = 81

Thus the five number summary is  21, 28, 33, 41, 81

Hence Option B is correct

8 0
3 years ago
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