(a-b)^2 = a^2-2ab+b^2
(8-5i)^2 = 8^2-2(8)(5i)+(5i)^2
= 64-80i+25i^2
i^2=-1
So
= 64-80i+25(-1)
=64-25-80i
= <em><u>39 - 80i</u></em>
which is your answer :)
Answer:
pls attach the question.....
Answer:
37 and 27
Step-by-step explanation:
Lets say that the two numbers are x and y. We get the equations x + y = 64 and x - y = 10. We can then add these two equations together to get, 2x = 74. Then we divide by two on both sides and get x = 37. We then plug this value back into the second equation and get that 37 - y = 10. We can simplify this and we get that y = 27. So our two numbers are 37 and 27.
Answer:
3:11
Step-by-step explanation:
3x=11y
<u>Rearrange to the format of the ratio.</u>
11y = 3x
<u>Let's find </u><u>y/x</u><u>. </u><u>y/x</u><u> is </u><u>y:x.</u>
11y = 3x
<u>Divide both sides by </u><u>11</u><u>.</u>
11y/11 = 3x/11
y = 3x/11
<u>NOW LET'S DIVIDE BOTH SIDES BY </u><u>x</u><u> TO GET </u><u>x</u><u> AS THE DENOMINATOR OF </u><u>y</u><u>.</u>
y = 3x/11
y/x = (3x/11)/x
y/x = (3x/11) * 1/x
y/x = 3/11
Therefore, y:x = 3:11
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