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Maksim231197 [3]
3 years ago
6

Look at this graph:

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

2

Step-by-step explanation:

slope=rise/run=20/10=2/1=2.

You might be interested in
X² - 14 = 50 what is x?
Klio2033 [76]

Answer:

x = 8

Step-by-step explanation:

x^{2} - 14 = 50

<u><em>You first need to add 14 to both sides:</em></u>

x^{2} - 14 = 50

  + 14   + 14

_________

x^{2} = 64

<u><em>To get rid of the square, you need to square root both sides:</em></u>

x^{2} = 64

\sqrt{x^2} = \sqrt{64}

<u><em>This gives you:</em></u>

x = 8, as your final answer.

3 0
3 years ago
And one math problem is <br><br><br> y=-2x+3<br> y=-7x-2
Novosadov [1.4K]

Answer:

x=-1, y=5. (-1, 5).

Step-by-step explanation:

y=-2x+3

y=-7x-2

-------------

-2x+3=-7x-2

-2x-(-7x)+3=-2

-2x+7x+3=-2

5x+3=-2

5x=-2-3

5x=-5

x=-5/5

x=-1

y=-2(-1)+3=2+3=5

8 0
3 years ago
Read 2 more answers
Please find what the value of x and y is!!!
beks73 [17]

Answer:

x = 3; y = 2

Step-by-step explanation:

You would just set each side equal to its opposite so for x, it'll be like:

4x+6=7x-3

and for y:

4y-3=3y+1

I attached my work below as well to help you.

7 0
3 years ago
A. 16%
k0ka [10]
I'd say it would be 24% but i may be wrong

8 0
4 years ago
Read 2 more answers
Which is an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12?
Bond [772]

Answer:

An equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

  • y=-\frac{1}{5}x+\frac{13}{5}

Step-by-step explanation:

Given the equation

5x - y = 12

converting the line into the slope-intercept form y = mx+b, where m is the slope

-y = 12-5x

y = 5x-12

The slope of the line = m = 5

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

Therefore, the slope of new line = – 1/m = -1/5 = -1/5

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the slope of new line = -1/5 and (-2, 3)

y-y_1=m\left(x-x_1\right)

y-3=-\frac{1}{5}\left(x-\left(-2\right)\right)

y-3=-\frac{1}{5}\left(x+2\right)

Add 3 to both sides

y-3+3=-\frac{1}{5}\left(x+2\right)+3

y=-\frac{1}{5}x+\frac{13}{5}

Therefore, an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

  • y=-\frac{1}{5}x+\frac{13}{5}
5 0
3 years ago
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