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Misha Larkins [42]
3 years ago
15

X + 5 + (-1) = -5x - 1

Mathematics
2 answers:
coldgirl [10]3 years ago
7 0

Answer:

-5/6 as fraction form

-0.83 as decimal form

Step-by-step explanation:

Good Luck

LenKa [72]3 years ago
4 0

Answer:

-5/6

^^that is if u want to find out x

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Given the function f(x) = x - 4, find f(-2).​
Mars2501 [29]

Answer: f(-2) = -6

Step-by-step explanation: f(-2) = -2 -4

                                                f(-2) = -6

6 0
2 years ago
Solve the equations. Make conclusion. 3|x+12|=6<br><br> *Please put down the steps also.*
Blababa [14]
3 | x+12 |=6
Start by distributing 3 to both x and 12
You get 3x+36=6
Subtract 36 from both sides
You then get 3x=-30
Divide 3 from both sides getting
x= -10
3 0
3 years ago
The area of a rectangular wall of a barn is 64 square feet. Its length is 8 feet longer than twice its width. Find the length an
ValentinkaMS [17]
L×w=64 ft^2...(1)
2w+8= l...(2)

l=64-w...(1a)

2w+8= 64-w
2w+w+8=64
3w=64-8
3w÷3= 56÷3
w=18.6'

l×w= 64
l×18.6= 64
l= 64÷18.6
l= 3.44 to the nearest hundredths.
6 0
3 years ago
Read 2 more answers
ms D ARRIVED AT SCHOOL AT 7:30 AM, SHE SPENT 35 MINUTES AT THE DINNER WITH A FRIEND IT TAKES HER 15 MINUTES TO GET TO SCHOOL WHA
Effectus [21]

Answer:

Ms D left at 6:40 AM

Step-by-step explanation:

Given:

MS D arrived at school at 7:30 AM

time spent for dinner = 35 mins

Time taken to to go to school = 15 mins

We will first find the Total time taken after leaving.

Total time taken can be calculated by adding time spent for dinner and Time taken to to go to school.

Total time taken after leaving = time spent for dinner + Time taken to to go to school = 35 +15 = 50 mins

MS D arrived at school at 7:30 AM.

Hence Time Ms D left  = Time She arrive at school - Total time taken after leaving = 7 hrs 30 min - 50 mins = 6 hrs 40 mins.

Hence Ms D left at 6:40 AM.

6 0
3 years ago
Find the area of quadrilateral ABCD. A. 27.28 units² B. 33.08 units² C. 28.53 units² D. 26.47 units²
Ludmilka [50]

Answer:

<h3>\boxed{ \boxed{ \bold{ \purple{ \sf{28.53 \:  {units}^{2} }}}}}</h3>

Option C is the correct option.

Step-by-step explanation:

For ABD

\sf{ =  \frac{2.89 + 8.59 + 8.6}{2} }

\sf{ =  \frac{20.08}{2} }

\sf{ = 10.04}

∆ ABD = \sf{ =  \sqrt{10.04(10.04 - 2.89)(10.04 - 8.59)(10.04 - 8.6)} }

\sf{  = \sqrt{10.04 \times 7.15 \times 1.45 \times 1.44 }}

\sf{  =  \sqrt{149.8891} }

\sf{ = 12.2429}

For ∆ ACD ,

\sf{s =  \frac{8.6 + 4.3 + 7.58}{2} }

\sf{ =   \frac{20.48}{2} }

\sf{ = 10.24}

∆ ACD = \sf{ =  \sqrt{10.24(10.24 - 8.6)(10.24 - 4.3)(10.24 - 7.58} }

\sf{ \sqrt{10.24 \times 1.64 \times 5.94 \times 2.66} }

\sf{ =  \sqrt{265.3456} }

\sf{ = 16.2894}

Area of quadrilateral ABCD = \sf{12.2429 + 16.2894}

\sf{ = 28.5323}

\sf{ = 28.53} units ²

Hope I helped!

Best regards!

8 0
3 years ago
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