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algol13
2 years ago
12

Factorize: cos4θ + sin3θ . cosθ

Mathematics
1 answer:
bekas [8.4K]2 years ago
7 0

Answer:

Hope this was help full.

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What is the answer to this question
My name is Ann [436]
It would be helpful if the picture showed the entire question
5 0
3 years ago
Ma poate ajuta cineva la acesta problema: pe o drepta g considerati punctele D, R,P si T coliniare in aceasta ordine astfel inca
valina [46]

Answer:

Givens

DR=PT=3cm and RP=4cm

Points D, R, P and T are collinear.

The image attached shows a representation of this problem.

By sum of segments, we have

DT=DR+RP+PT

Replacing all given values, we have

DT=3+4+3=10 \ cm

Therefore, the segment DT is 10 centimeters long.

Now, we know that point E is the center of segment RP, which means is a middle point, divides the segment equally. So, to prove that segment DT is symmetrical regarding point E, we need to prove that both sides are equal.

RE=EP=2cm, by definition of middle point.

By sum of segments, we have

DR+RE=3+2=5cm\\EP+PT=5cm

Which means DR+RE=\frac{DT}{2}\\ EP+PT=\frac{DT}{2}.

Therefore, segment DT is symmetrical regarding point E.

8 0
3 years ago
How do you delete answers?
Gekata [30.6K]

Answer:

????????.......?????????????????

if we asked questions and somone just ans the question wrongly for free points

therefore you can report the ans and delete the ans..

now a days many people are doing this...

3 0
3 years ago
Read 2 more answers
Rewrite each of these statements so that negations appear only within predicates (that is, so that no negation is outside a quan
Ghella [55]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

In point a:

¬∃y∃xP (x, y)  

∀x∀y(>P(x,y))  

In point b:

¬∀x∃yP (x, y)

 ∃x∀y  ¬P(x,y)

In point c:

¬∃y(Q(y) ∧ ∀x¬R(x, y)) \equiv  ∀y(> Q(y) V ∀ ¬ (¬R(x,y)))

∀y(¬Q(Y)) V ∃xR(x,y) )

In point d:

¬∃y(∃xR(x, y) ∨ ∀xS(x, y))  

∀y(∀x>R(x,y)) \wedge ∃x>s(x,y))

In point e:

¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))

∀y(∃x ∀z)>T(x,y,z) \wedge ∀x ∃z> V (x,y,z))  

8 0
3 years ago
A book with 650 pages has 3 pages with diagrams.
Mrac [35]

The pages that have diagrams is an illustration of proportions

0.46% pages have diagrams

<h3>How to determine the percentage</h3>

The given parameters are:

Total = 650 pages

Diagrams = 3 pages

The percentage of page that has diagram is then calculated as:

Diagram\% = \frac{Diagrams}{Total} * 100\%

So, we have:

Diagram\% = \frac{3}{650} * 100\%

Evaluate the product

Diagram\% = \frac{300}{650} \%

Divide

Diagram\% = 0.46 \%

Hence, 0.46% pages have diagrams

Read more about proportions at:

brainly.com/question/1781657

3 0
2 years ago
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