Factorize: cos4θ + sin3θ . cosθ
1 answer:
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Answer:
Givens
and
Points D, R, P and T are collinear.
The image attached shows a representation of this problem.
By sum of segments, we have
Replacing all given values, we have
Therefore, the segment DT is 10 centimeters long.
Now, we know that point E is the center of segment RP, which means is a middle point, divides the segment equally. So, to prove that segment DT is symmetrical regarding point E, we need to prove that both sides are equal.
, by definition of middle point.
By sum of segments, we have
Which means .
Therefore, segment DT is symmetrical regarding point E.
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) ∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) ∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
The pages that have diagrams is an illustration of proportions
0.46% pages have diagrams
<h3>How to determine the percentage</h3>The given parameters are:
Total = 650 pages
Diagrams = 3 pages
The percentage of page that has diagram is then calculated as:
So, we have:
Evaluate the product
Divide
Hence, 0.46% pages have diagrams
Read more about proportions at: