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andrey2020 [161]
3 years ago
7

Hello! please help with this question.

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
3 0

Answer:

D

Step-by-step explanation:

A) more like parallel line

B) That is angle bisecting

C) Neither Angle or line bisector

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As a marketing manager, you are tasked with selecting a website to place your advertisement. The following sampled data shows th
olasank [31]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Website 1 : 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 377999 / 36 = 10499.9722

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 1 :), s = 110.239865

Website 2 : 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 395197 / 36 = 10977.6944

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 2), s = 132.617995

2.)

Yes, the viewership between the two websites are different with the second website has a higher mean viewership with a mean of 10977.6944.

3.)

The probability of 12000 views per month on each website :

Probability = Mean viewership per month / required viewership

Website 1 :

P(12000) = 10499.9722 / 12000 = 0.8749

Website 2 :

P(12000) = 10977.6944 / 12000 = 0.9148

4.)

More consistent website :

We use the standard deviation value, the higher the standard deviation, the higher the variability :

Website 1 should be more consistent has it has a Lower standard deviation score, hence, should show lower variability than website 2.

5.)

Website suitable for advertisement should be one with higher viewership per month in other to reach a larger audience. Hence, website 2 should be recommended for advertisement.

5 0
2 years ago
Add three data values to the following data set so the mean increases by 10 but the median does not change. The numbers are 42 3
777dan777 [17]
In order the numbers are 20, 29, 32, 37, 42.
So that means the median is 32. In order for the median to stay the same one of the three data values must be 32 as well as adding a number to each side of the ends. One 32 or less another 32or more.
The mean right now is: 20+29+32+37+42=160 and there are 5 values.
Mean: 160/5=32
For it to increase by 10 it has to be 42.
extra 3 numbers I used were 31, 32, & 113 (those are your answer)
3 0
3 years ago
the probability that Jenya receives spam email is 4%.if she receives 520 email in a week about how much will be spam
wariber [46]
520*.04=20.8, or closer to 21 spam emails.
6 0
3 years ago
Name the following segment or point
babunello [35]

Answer:

The answer would be the third option, segment AS

5 0
2 years ago
ME AJUDEM PFV!!O valor da expressão (NA FOTO)simplificada é:
koban [17]

D) 16.

Espero que esto ayude hermano.

7 0
3 years ago
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