CD = x
BC = y
AB = 85
BD = BC+CD = y+x
tan(angle) = opposite/adjacent
tan(28) = BC/AB
tan(28) = y/85
85*tan(28) = y
y = 85*tan(28)
y = 45.1953016912257
tan(angle) = opposite/adjacent
tan(31) = BD/AB
tan(31) = (y+x)/85
tan(31) = (45.1953016912257+x)/85
85*tan(31) = 45.1953016912257+x
51.0731526173427 = 45.1953016912257+x
51.0731526173427-45.1953016912257 = 45.1953016912257+x-45.1953016912257
5.877850926117 = x
x = 5.877850926117
So CD is roughly 5.877850926117 meters
This problem can be seen as a rectangle triangle where the vertices are:
Vertice 1: home plate
Vertice 2: First base
Vertice 3: second base.
Right angle between vertice 1 and 2 and vertice 2 and 3.
Distance between each base in 90 '.
Calculating then the distance between home plate and second base we have:
d = root ((90) ^ 2 + (90) ^ 2)
d = 127.28 feets
answer:
the distance between home plate and second base is 127.28 feets
Use the ! tool to find the # of combinations.
8!/5! = 40,320/120 = 336
There are many answers for this and this is one of them:
Y = 4(3 + 1)
Y = 16
Keep in mind that, when the logarithm base is not explicitly written, base 10 is assumed, therefore,
