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SVETLANKA909090 [29]
3 years ago
14

The graph shows the result of a matrix transformation, where the pre-image has dashed lines Which matrix operation is represente

d in the graph?

Mathematics
1 answer:
diamong [38]3 years ago
3 0

The <em>matrix operation</em> is the <em>addition subtraction </em>and <em>multiplication </em>involving matrices.  The coordinates of the <em>image </em>can be represented as a matrix obtained from the coordinates of the <em>preimage </em>through matrix operations

The best correct option is<u> option D)</u>,<em> (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows</em>:

\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the <em>coordinates</em> of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The <em>coordinates </em>of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the  vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by <em>multiplying by</em> (-1)

Therefore, the required matrix operation is presented as follows:

\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]

Therefore, the <em>best correct</em> option is option D)

Learn more about matrix operations here:

brainly.com/question/17141646

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Answer:

Step-by-step explanation:

From the information given:

We can compute the required calculations into a table as shown below.

\mathbf{Data \ value  }       \mathbf{ Frequency   } \mathbf{Relative  \ frequency}   \mathbf{Cumulative \  relative }

                                                                                              \mathbf{Frequency}

5                                     14                14/65 = 0.22                           14  

6                                     19                19/65 = 0.29               19+14 = 33

7                                      12                12/65 = 0.19               33+12 = 45

8                                       9                 9/65 = 0.14               45 + 9 = 54

9                                 <u>     11     </u>            11/65  = 0.17              54 + 11 = 65

                                        65

Note: that the relative frequency is determined by  dividing each value in the frequency by the total of the frequency.                        

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Answer:

B.

Step-by-step explanation:

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14.What is the solution of the system?
Archy [21]

Answer:

14.  x=-2.5,  y = -7

15.  x=28  y = -20

Step-by-step explanation:

14.  Let's solve this system by elimination.  Multiply the first equation by -1.

-1*(4x-y)= -1*(- 3)

-4x +y = 3

Then add this to the second equation.

-4x+y = 3

6x-y= - 8

--------------

2x   = -5


Divide each side by 2

x = -2.5

We still need to find y

-4x+y =3

-4(-2.5) + y =3

10 +y =3

Subtract 10 from each side.

y = 3-10

y = -7


15.I will again use elimination to solve this system, because using substitution will give me fractions which are harder to work with.   I will elimiate the y variable.  Multiply the first equation by 11

11( 5x+6y)= 11*20

55x+66y = 220

Multiply the second equation by -6

-6(9x+11y)=32*(-6)

-54x-66y = -192


Add the modified equations together.

55x+66y = 220

-54x-66y = -192

---------------------------

x = 28

We still need to solve for y

5x+6y = 20

5*28 + 6y =20

140 + 6y = 20

Subtract 140 from each side

6y = -120

Divide by 6

y = -20

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