3 years ago

Ingiliz halkı ablanız oğula gidiyur

Mathematics

1 answer:

AnnyKZ [126]3 years ago

4 0

Step-by-step explanation:

<h3>Özür dilerim seni kırdığım için öleceğiz okkk</h3>

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1. Differentiate with respect to x:<br>

natta225 [31]

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Answer:

a) y' = x^2(3x·ln(6x) +1)

b) y' = 6e^(3x)/(1 -e^(3x))^2

Step-by-step explanation:

The applicable rules for derivatives include ...

d(u^n)/dx = n·u^(n-1)·du/dx

d(uv)/dx = (du/dx)v +u(dv/dx)

d(e^u)/dx = e^u·du/dx

d(ln(u))/dx = 1/u·du/dx

(a)

$y=x^3\ln{(6x)}\\\\y'=3x^2\ln{(6x)}+\dfrac{x^3\cdot6}{6x}\\\\\boxed{\dfrac{dy}{dx}=3x^3\ln{(6x)}+x^2}$

(b)

$y=\dfrac{1+e^{3x}}{1-e^{3x}}=1+\dfrac{2}{1-e^{3x}}=1+2(1-e^{3x})^{-1}\\\\y'=-2(1-e^{3x})^{-2} (-3e^{3x})\\\\\boxed{\dfrac{dy}{dx}=\dfrac{6e^{3x}}{(1-e^{3x})^2}}$

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3 years ago

Ingiliz halkı ablanız oğula gidiyur​

Ingiliz halkı ablanız oğula gidiyur