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STALIN [3.7K]
3 years ago
6

2^3+3^2 ..........................

Mathematics
2 answers:
IrinaVladis [17]3 years ago
5 0

Answer:

17

Step-by-step explanation:

2^3+3^2\\8+9\\17

Dafna11 [192]3 years ago
3 0

Answer:

17 is the answer

Step-by-step explanation:

  • 2³+3²
  • 8+9
  • 17
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F(x)=2^x. What is g(x)?
Alexxx [7]

The function g(x) is g(x)= (3x)^2

<h3>How to solve for g(x)?</h3>

The complete question is in the image


From the graph in the image, we have:

f(x) = x^2

The function f(x) is stretched by a factor of 3 to form g(x).

This means that:

g(x) = f(3x)

So, we have:

g(x)= (3x)^2

Hence, the function g(x) is g(x)= (3x)^2

Read more about function transformation at:

brainly.com/question/10222182

#SPJ1

7 0
2 years ago
Let the (x; y) coordinates represent locations on the ground. The height h of
grigory [225]

The critical points of <em>h(x,y)</em> occur wherever its partial derivatives h_x and h_y vanish simultaneously. We have

h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5

Substitute <em>y</em> in the second equation and solve for <em>x</em>, then for <em>y</em> :

2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}

This is to say there are two critical points,

(x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)

To classify these critical points, we carry out the second partial derivative test. <em>h(x,y)</em> has Hessian

H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}

whose determinant is 192y-16. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and h_{xx} are positive at the point, then it's a local minimum

• if the determinant is positive and h_{xx} is negative, then it's a local maximum

• otherwise the test fails

We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

while

\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0

So, we end up with

h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}

7 0
3 years ago
Please help dont want to fail final exam
olga nikolaevna [1]

Answer:

$75 I think. Not 100% sure but like 95% sure :)

4 0
3 years ago
Every week, Hector works 20 hours and earns $210.00. He earns a constant amount of money per hour.
baherus [9]
The answer is 40.

H - hours W - weeks
20 x 2 = 40
5 0
3 years ago
How high is a tree that casts a 25 ft shadow at the same time a 7ft pole casts a shadow which is 4 ft long?
Olegator [25]

Answer:

x=12

Step-by-step explanation:

height of tree)/(shadow length of tree) = (height of pole)/(shadow length of pole)

x/26 = 6/13

13x = 26*6

13x = 156

x = 156/13

x = 12

(hope this helps can i plz have brainlist :D hehe)

4 0
3 years ago
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