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2 years ago

TEST PLZ HELP FOR POINTS

Mathematics

2 answers:

77julia77 [94]2 years ago

7 0

My best answer will be 12

dmitriy555 [2]2 years ago

5 0

Answer:

the answer is 32 for sure

Step-by-step explanation:

pretend that they are two triangles opposite to each other and the use the Pythagoras Theorem

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What is 1+1 (hint 11)

Leviafan [203]

no it's 22 :D...............

5 0

2 years ago

In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 15 boys an

denis-greek [22]

Answer:

There are a total of possible 1820 results.

Step-by-step explanation:

Since there are two competitions, one for boys and one for girls, and we want all the possible results we will calculate the possible combinations for the boys and multiply them by the possible combinations for the girls. This is shown below:

$Boys = \frac{15!}{3!(15 - 3)!} = \frac{15!}{3!12!} = \frac{15*14*13*12!}{3!12!}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = 455$

$Girls = \frac{4!}{3!*(4 - 3)!}\\Girls = \frac{4*3!}{3!}\\Girls = 4$

Total number of possible results:

$results = 4*455\\results = 1820$

3 0

3 years ago

Please help, if you know the correct answer! Only if you know the correct answer!

My name is Ann [436]

It is the correct answer
Hope this help u

4 0

3 years ago

Find y when x=77, if y varies inversly as x, and y = 23 when x = 115.

Eduardwww [97]

The required value of y is 2645 / 77 when x = 77.

Step-by-step explanation:

1. Let's check the information given to answer:

if y varies inversely as x, and y = 23 when x = 115. Find y when x=77

2. What is y when x = 77?

As the statement "y varies inversely as x" translates into y = k/x

If we let y = 23 and x = 115, the constant of variation becomes

23 = k ÷ 115

k = 23 × 115

k = 2645

Thus the specification equation is y = 2645 ÷ x . Now, letting x = 77, we obtain

y = 2645 ÷ x

y = 2645 ÷ 77

So, The required value of y = 2645 / 77 when x = 77

#learnwithBrainly

7 0

3 years ago

April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how

Ostrovityanka [42]

40 adult tickets were sold and 35 children tickets were sold

Solution:

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 8

Cost of 1 children ticket = $ 5

Given that April sold 75 tickets to the school Christmas play and collected $495

Number of tickets sold = 75

number of adult tickets sold + number of children tickets sold = 75

a + c = 75 ----- eqn 1

Given that April collected $495

Thus we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495

$a \times 8 + c \times 5 = 495$

8a + 5c = 495 ----- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "c"

From eqn 1,

a = 75 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8(75 - c) + 5c = 495

600 - 8c + 5c = 495

-3c = 495 - 600

-3c = - 105

Substitute c = 35 in eqn 3

a = 75 - 35

Thus 40 adult tickets were sold and 35 children tickets were sold

8 0

3 years ago