All categories

3 years ago

How can you make 19 out of 10 8 5 2 3

Mathematics

2 answers:

postnew [5]3 years ago

7 0

8-2=6
10+6+3=19

I’m not sure if you are allowed to do it that way so I can find other ways if needed

maks197457 [2]3 years ago

4 0

Answer:

Step-by-step explanation:

10×3+2-(8+5)

10×3+2-13

30+2-13

32-13

You might be interested in

In triangle ABC, c = 8, b = 6, and ∠C = 60°. sin∠B = _____

satela [25.4K]

Hello,

sin B/b=sin C/c
==>sin B=√3 / 2 * 6/8=3√3 /8

6 0

3 years ago

Read 2 more answers

Perform the following food service calculation. Size of juice can = 54 oz. Portions of juice served = 6 oz. Number of cases used

Vedmedyk [2.9K]

2 cases x 12 cans = 24 cans

24 cans x 54 oz per can = 1296 oz

1296 oz / 6 oz per serving = 216 guests served

4 0

3 years ago

Read 2 more answers

This lesson is almost ⅔ over. Express this number as a decimal.

MissTica

Answer:

0.66666667

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

SHOW WORK A car travels 174 miles in 3 hours. At this rate, how many miles will the car travel in 12 hour?

polet [3.4K]

Answer:

522 miles

Step-by-step explanation:

174 x 4 = 522

5 0

3 years ago

Read 2 more answers

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago