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Lady_Fox [76]
3 years ago
8

6,1,3,8,5,11,1,5 mad

Mathematics
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer:

Step-by-step explanation:

mean=40/8=5

MAD=(|6-5|+|1-5|+|3-5|+|11-5|+|1-5|+|5-5|)/8

=(1+4+2+6+4+0)/8

=17/8=2,125

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9.2 = x
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3 years ago
Sketch the graph, showing one complete cycle. State the period and amplitude, and the greatest and least values of yy=3sin(θ−π/2
Alborosie
Explanation:

Consider the following general periodic function:

y=a\sin b(\theta\text{ -h})\text{ +k}

where

a= amplitude

b = frecuency

h= phase translation

k= vertical translation

2π/ |b| = period

Now, consider the following periodic function:

y=3sin(\theta\text{ -}\frac{\pi}{2})

Applying the definition given at the beginning of this explanation, we can see that:

a = amplitude = 3

2π/ |b| = period = 2π/|1| = 2π

Then, the graph of the given function is:

Notice that the greatest and least values of y are 3 and -3 respectively.

We can conclude that the correct answer is:

Answer:

Graph:

Period:

2π

Amplitude:

3

The greatest value of y (coordinate y of the maximum point):

3

The least value of y (coordinate y of the minimum point):

\text{ -3}

3 0
1 year ago
Jim, Sergio, Sarah, Tyrone, Dawn, Simone, Maria, and Katrina have all been invited to a dinner party. They arrive randomly and e
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Answer:

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5 0
4 years ago
The larger of two numbers is 7 times the smaller number. 3 times the larger number is 7 more than 4 times the smaller number. Fi
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So the larger number is x, and the smaller number is y
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valina [46]

Answer:

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Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

B_1,B_2 denote the two boxes.

In box B_1:

No. of black balls = 1

No. of white balls = 1

In box B_2:

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes B_1,B_2 is chosen is \frac{1}{2}

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To find:probability that the marble is black

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6 0
3 years ago
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