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Burka [1]
3 years ago
12

Please help I’m really stuck

Mathematics
1 answer:
motikmotik3 years ago
7 0

Answer:

A is the correct answer

have a great day

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10y less than or equal to 12x
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10y <= 12x

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An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal. Find the force necessary to prevent the car fro
Misha Larkins [42]

Answer:

1931.7N

Step-by-step explanation:

We are told in the question that :

An auto ( a car) weighs = 2500 pounds

It s inclined at n horizontal Ange of 10°

We are asked to find the force that would prevents it from rolling down the street.

Since the unit for Force = Newton or kgm/s²

Step 1

Convert Weight in pounds to kg

1 pound = 0.453592kg

2500 pounds =

2500 pounds × 0.453592kg

= 1133.981kg

Step 2

Find the force that would prevents it from rolling down the street.

Force = Mass × Acceleration due to gravity × sin θ

Acceleration due to gravity = 9.81m/s

Force = 1133.981kg × 9.81 × sin 10°

Force = 1931.7237321 N

Approximately = 1931.7N

4 0
3 years ago
Use the graph to find the following.
Levart [38]

a) Local maximum values of g are: 0 and 3

b) The values at which g has local maximum are : -2 and 2

<h3>What is a maximum point?</h3>

A maximum point is the point at which the gradient of the curve changes from positive to negative.

Analysis:

The inverted v-curves all have maximum values and they are two.

The one at x = -2 and the one at x = 2 for in both cases their maximum values are y = 0 and y = 3 respectively.

Learn more about minimum and maximum points:  brainly.com/question/14993153

#SPJ1

5 0
2 years ago
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