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3 years ago

Please help I’m really stuck

Mathematics

1 answer:

motikmotik3 years ago

7 0

Answer:

A is the correct answer

have a great day

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Which of the following is an extraneous solution of the square root of -3x-2=x+2

yarga [219]

Answer:

x=-6 is an extraneous solution

Step-by-step explanation:

we have

$\sqrt{-3x-2} =x+2$

squared both sides

$-3x-2=(x+2)^2$

$-3x-2=x^2+4x+4$

$x^2+7x+6=0$

solve the quadratic equation by graphing

The solution is x=-6 and x=-1

see the attached figure

Verify each solution

substitute the value of x in the original expression

For x=-6

$\sqrt{-3(-6)-2} =-6+2$

$\sqrt{16} =-4$

$4=-4$ ----> is not true

Is an extraneous solution

For x=-1

$\sqrt{-3(-1)-2} =-1+2$

$\sqrt{1} =1$

$1=1$ ----> is true

Is the solution

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3 years ago

Your class has 18 students. Exactly 2/3 of them say that, out of all their subjects, they like science the most. Which model sho

Aleksandr [31]

Ok so I need the models to answer this question.

5 0

3 years ago

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Which congruence statement is true.!?

andreyandreev [35.5K]

Step-by-step explanation:

$\\ \triangle ABC \cong \triangle DFE \\$

6 0

3 years ago

-2x-2+x^2+x+180+-2x-2=180

Dominik [7]

Answer:

x= 4, -1

Step-by-step explanation:

-2x - 2 + x^2 + x + 180 - 2x - 2 = 180

add like terms and put in descending order

x^2 - 3x + 176 = 180

subtract 180 from both sides

x^2 - 3x - 4 = 0

factor out the equation

(x-4)(x+1)=0

solve for x

x-4=0 x+1=0

x=4 x=-1

5 0

3 years ago

A(1) = -11 a(n) = a(n − 1). 10 What is the 4th term in the sequence?

neonofarm [45]

Answer:

a(n)= a(n-1) .10

Clearly see the equation

you can do it directly Apply logic

Every n th term is 10 times of previous n-1 th term

That is common ratio an/a(n-1)= 10

So, We have to find 4 th term

So, 4 th term is simply

1st term × (common ratio)^(4-1)

-11( 10)^3

-11000

Thanks

3 0

3 years ago