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2 years ago

A mile is 5280 feet. How many miles per hour is equal to 528 feet per minute?

Mathematics

1 answer:

Tresset [83]2 years ago

5 0

Answer:

0.1 mph

Step-by-step explanation:

5280 and 528 are one space thingy away (sorry I forgot what its actually called) so to go one up it would be ×10 and down ÷10. 5280 is 1mph and 1÷10=0.1 so its 0.1

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there are 6 glass bottles and eight plastic bottles on a rack. I f one is chosen at random, what is the probability of picking a

netineya [11]

Answer:

6:8

Step-by-step explanation:

6 is the ratio of glass bottles and 8 is the plastic or you can put 3:4 because you divide the number b 2

3 0

3 years ago

Needhdjdjdjdjdjdnhiskdjdjdjdjdjdjjshdjdjdjdjdjdjdjd<br><br>

Lilit [14]

9514 1404 393

Answer:

-(√2)/2

Step-by-step explanation:

The expression evaluated at n=a gives the indeterminate form 0/0, so L'Hopital's rule can be used to find the limit. The second expression comes from differentiating numerator and denominator. Then the form with n=a is no longer indeterminate.

$\displaystyle\lim_{n\to a}{\frac{\sqrt{2n}-\sqrt{3n-a}}{\sqrt{n}-\sqrt{a}}}=\lim_{n\to a}{\frac{\frac{2}{2\sqrt{2n}}-\frac{3}{2\sqrt{3n-a}}}{\frac{1}{2\sqrt{n}}-0}}\\\\=\sqrt{a}\left(\frac{2}{\sqrt{2a}}-\frac{3}{\sqrt{3a-a}}}\right)=\boxed{-\frac{1}{\sqrt{2}}}$

5 0

3 years ago

After a long practice, the marching band drank an entire 15 gallon cooler of water. The foot ball team drank 1/3 less than that.

astra-53 [7]

Answer:

the football team drank 10 gallons of water

Step-by-step explanation:

if the football team drank 1/3 less than 15, 1/3 of 15 is 5 so you would then subtract 5 from 15 and you get 10

6 0

3 years ago

What is the solution of -8/2y-8=5/y+4 - 7y+8/y^2-16

blsea [12.9K]

Answer:

Step-by-step explanation:

$Domain:\\\\2y-8\neq0\ \wedge\ y+4\neq0\ \wedge\ y^2-16\neq0\\\\2y\neq8\ \wedge\ y\neq-4\ \wedge\ y^2\neq16\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq\pm\sqrt{16}\\\\y\neq4\ \wedge\ y\neq-4\ \wedge\ y\neq-4\ \wedge\ y\neq4\\\\\boxed{y\neq-4\ \wedge\ y\neq4}\\\\===========================$

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-4^2}\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}\qquad\text{multiply both sides by (-2)}\\\\\dfrac{8}{y-4}=-\dfrac{10}{y+4}+\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{add}\ \dfrac{10}{y+4}\ \text{to both sides}\\\\\dfrac{8}{y-4}+\dfrac{10}{y+4}=\dfrac{14y+16}{(y-4)(y+4)}$

$\dfrac{8(y+4)}{(y-4)(y+4)}+\dfrac{10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{8(y+4)+10(y-4)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{use the distributive property}\\\\\dfrac{8y+32+10y-40}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\qquad\text{combine like terms}\\\\\dfrac{(8y+10y)+(32-40)}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\\\\\dfrac{18y-8}{(y-4)(y+4)}=\dfrac{14y+16}{(y-4)(y+4)}\iff18y-8=14y+16\\\\18y-8=14y+16\qquad\text{subtract 14y from both sides}$

$4y-8=16\qquad\text{add 8 to both sides}\\\\4y=24\qquad\text{divide both sides by 4}\\\\y=8\in D$

8 0

3 years ago

I WANT SOLUTION AND EXPLANATION ANSWER IS GIVEN AT LAST!!!

Pavel [41]

<h3><u>Question:</u></h3>

The present ages of Ram and Rehman are in the ratio 8:9. After 5 years, the ratio of their ages will be 9:10. Find their present ages.

<h3><u>Statement:</u></h3>

The present ages of Ram and Rehman are in the ratio 8:9. After 5 years, the ratio of their ages will be 9:10.

<h3><u>Solution:</u></h3>

Let the present age of Ram and Rehman be 8x years and 9x years respectively.
After 5 years, their ages will be 9x years and 10 years respectively.
Therefore, by the problem

$\frac{8x + 5}{9x + 5} = \frac{9}{10} \\ = > 10(8x + 5) = 9(9x + 5) \\ = > 80x + 50 = 81x + 45 \\ = > 50 - 45 = 81x - 80x \\ = > x = 5$

So, the present age of Ram = 8x years = (8×5) years = 40 years
The present age of Rehman = 9x years = (9×5) years = 45 years

<h3><u>Answer:</u></h3>

The present ages of Ram and Rehman are 40 years and 45 years respectively.

3 0

2 years ago