For this case we have a function of the form 
. Where:
By definition, the domain of a function is represented by the set of values of the independent variable, x, for which the value of the variable y can be calculated.
For its part, the range is represented by the values of "and".
So:
Thus, the range is {-3,1,2}
Answer:
{-3,1,2}
The inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
a(n) = 3n - 30
To find make subject n and solve
a(n) + 30 = 3n
Plug n = n(a) and a(n) = a
Thus, the inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.
Learn more about the function here:
brainly.com/question/5245372
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<h3>
Answer: 29</h3>
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Work Shown:
The two angles shown are a linear pair. They are adjacent and supplementary. Supplementary angles add to 180 degrees.
(4x-5)+(x+40) = 180
5x+35 = 180
5x = 180-35
5x = 145
x = 145/5
x = 29
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As a check, if x = 29, then
4x-5 = 4*29-5 = 116-5 = 111
x+40 = 29+40 = 69
The two angles are 69 and 111 degrees which add to 69+111 = 180, which helps confirm the answer.
613 liters total. 295+318=613 liters
9514 1404 393
Answer:
a) 4
b) 3
Step-by-step explanation:
a. The total number of real and complex zeros is equal to the degree of the polynomial. That total is (1 negative real) + (3 positive real/complex) = 4 total zeros. The degree of the polynomial is 4.
The even degree is confirmed by the answer to part b, and by the end-behavior shown in the table, which has a tendency to -∞ for |x|→∞.
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b. The intermediate value theorem tells you there will be zeros in the intervals (0, 1), (1, 2), and (2, 3) according to the values in the table. (The function changes sign in those intervals.) Thus there are 3 positive real zeros.
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<em>Additional comment</em>
Stanley cannot tell anything about Descartes' rule of signs by analyzing the table of function values. To use that rule, he must have terms of the polynomial. If he has those terms, he already knows the degree of the polynomial.
