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2 years ago

1/6 (12 -6x) = 5 (x+4) plz help.

Mathematics

2 answers:

Scorpion4ik [409]2 years ago

6 0

Answer:

$\frac{1}{6} (12 - 6x) = 5(x + 4) \\ \frac{12}{6} - \frac{6x}{6} = 5x + 5 \times 4 \\ 2 - x = 5x + 20 \\ x \: terms \: togather \\ 5x + x = 2 - 20 \\ 6x = - 18 \\ x = \frac{ - 18}{6} \\ x= - 3 \\ thank \: you$

Romashka-Z-Leto [24]2 years ago

5 0

52/41 in to decimal 1.2682

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goblinko [34]

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mote1985 [20]

GIVEN:

We are given the following polynomial;

$x^3+x^2+4x+4$

Required;

We are required to factorize this polynomial completely.

Step-by-step explanation;

To factorize this polynomial, we start by grouping;

$(x^3+x^2)+(4x+4)$

We now take the common factor in each group;

$\begin{gathered} x^2(x+1)+4(x+1) \\ \\ (x^2+4)(x+1) \end{gathered}$

Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;

$\begin{gathered} x^2+4=0 \\ \\ Subtract\text{ }4\text{ }from\text{ }both\text{ }sides: \\ \\ x^2=-4 \\ \\ Take\text{ }the\text{ }square\text{ }root\text{ }of\text{ }both\text{ }sides: \\ \\ x=\pm\sqrt{-4} \\ \\ x=(\pm\sqrt{-1}\times\sqrt{4}) \\ \\ x=\pm2i \end{gathered}$

Therefore, the factors of the other parenthesis are;

$(x+2i)(x-2i)$

Therefore, the complete factorization of the polynomial is;

ANSWER:

$(x+1)(x+2i)(x-2i)$

Option C is the correct answer.

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Step-by-step explanation:

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Firdavs [7]

Answer:

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Step-by-step explanation:

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