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solmaris [256]
2 years ago
14

Javier walks from his home at point K to the Internet café at point O. If the school at point W is exactly halfway between Javie

r's house and the Internet café, how far does Javier walk?
(19p-5) m (15p+23) m
l----------------------------------------------------------l------------------------------------------------------------------l
K W O
Mathematics
2 answers:
TiliK225 [7]2 years ago
6 0

Answer:

16 m

Hopefully this helps!

Please mark as brainliest!

sveta [45]2 years ago
4 0

Answer:

Step-by-step explanation:

16 m

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SOMEONE HELPFUL PLZ ANSWER!!!!!!!! WILL MARK BRAINLIEST!!!!!!!!!
Eva8 [605]

Answer:

a , c , b

Step-by-step explanation:

just input the numbers in a TI 84 calculator (if you don't have I would be happy to show you how to download the free online version.) And sort from greatest to least.

3 0
2 years ago
Read 2 more answers
Which expressions are equivalent to 1 divided m/6? Check all that apply
jenyasd209 [6]

Answer:

option A, option C, option D

Step-by-step explanation:

a) 1 ÷ m/6

can be written as

\frac{1}{1}÷ \frac{m}{6}

b) sides in (m/6) will change if both has to multiply

c) 1 ÷ m/6

can be written as

1 * 6/m

1(\frac{6}{m}) and wont make change to answer. so matches with the question.

d)

1 ÷ m/6

1 * 6/m

1 * 6 * \frac{1}{m}

6 * \frac{1}{m}

6 ÷ m ..therefore true

e)

1 ÷ m/6

1 * 6/m

6/m    ....does not match or can be converted to the following so wrong

  • Therefore A, C, D are correct and B and E is wrong.
6 0
2 years ago
Simplify.. The square root of 8/18. A. -2/3. B. 2/3. C.2. D. 3/2
ira [324]
8/18 = 4/9 ( divide both numerator and denominator by 2 )
√4 = 2  and √9 = 3
\sqrt{ \frac{8}{18} } =  \sqrt{ \frac{4}{9} } =  \frac{2}{3}
Answer:  B ) 2/3
4 0
3 years ago
Read 2 more answers
How do I do functions
choli [55]

Explanation:

It depends on what you want to do. The topic of functions is easily a semester course in algebra, at least.

__

A function is a relation that maps an input to a single output. Common representations are ...

  • list of ordered pairs
  • table
  • graph
  • equation

Functions sometimes take multiple inputs to generate a given output.

Often, one of the first things you're concerned with is whether a given relation <em>is</em> a function. It <u><em>is not</em></u> a function if a given input maps to more than one output.

We say a relation <em>passes the vertical line test</em> when a vertical line through its graph cannot intersect the graph in more than one point. Such a relation <em>is a function</em>.

__

When a function is written in equation form, it is often given a name (usually from the (early) middle of the alphabet. Common function names are f, g, h. Any name can be used.

When a function is defined by an equation, the variables that are inputs to the function are usually listed in parentheses after the function name:

  f(x), g(a, b), h(m)

These variables show up in the function definition that follows the equal sign:

  f(x) = 3x -4

  g(a, b) = (1/2)a·b

  h(m) = 1/(m^3 +3) +5

The listed variable is called the "argument" of the function.

This sort of form of an equation is sometimes called "functional form." That is, a dependent variable, such as y, can be defined by ...

  y = 3x +4

or the same relation can be written in functional form as ...

  f(x) = 3x +4

Sometimes students are confused by this notation, thinking that f(x) means the product of f and x. Yes it looks like that, but no, that's not what it means.

__

One of the first things we like to do with functions is <em>evaluate</em> them. This means we put a particular value wherever the variable shows up.

If we want to evaluate the above f(x) for x=2, we put 2 (every)where x is:

  f(x) = 3·x -4

  f(2) = 3·2 -4 = 6 -4 = 2

We can evaluate the function for literals, also.

  f(a) = 3a -4

  f(x+h) = 3(x+h) -4 = 3x +3h -4 . . . here, h is a variable, not the function name

__

We can add, subtract, multiply, divide functions, and we can compute functions of functions. The latter is called a "composition", and is signified by a centered circle between the function names.

<u>Add functions</u>: f(x) +h(x) = (3x +4) +(1/(x^3 +3) +5)

  also written as (f+h)(x)

<u>Subtract functions</u>: f(x) -h(x) = (3x +4) -(1/(x^3 +3) +5)

  also written as (f-h)(x)

<u>Multiply functions</u>: f(x)·h(x) = (3x +4)(1/(x^3 +3) +5)

  also written as (f·h)(x) or (fh)(x)

<u>Divide functions</u>: h(x)/f(x) = (1/(x^3 +3) +5)/(3x +4)

  also written as (h/f)(x)

<u>Function of a function (composition)</u>: f(h(x)) = f(1/(x^3 +3) +5) = 3(1/(x^3 +3) +5) +4

  also written as (f∘h)(x) . . . . . the symbol ∘ is called a "ring operator". Sometimes a lower-case 'o' is used in plain text. It is not a period or dot or zero or degree symbol. Note the sequence of names means function f operates on the result of function h.

As with other function evaluations, the inner parentheses are evaluated first, and that result is then used as the argument of the outer function.

__

Because a function name can stand for an algebraic expression of arbitrary complexity, we often use a function name to talk about the properties of expressions in general.

For example, if we want to reflect the graph of the function y = f(x) over the x-axis, we want to change the sign of every y-value. We can use function notation to write that idea as ...

  y = -f(x) . . . . . f(x) reflected over the x-axis

The attached graph shows an example using the above function h(m).

4 0
3 years ago
10x+8(1/3 x + 2/3) =-20
ra1l [238]

Answer:

hiii

Step-by-step explanation:

1. Multiply both sides by 3

38/3x x 3 +16/3. x =-20x3

2. Simplfy

38x+16=-60

3. Subtract 16 from both sides

38x+16-16=-60-16

4. Simplfy

38x=-76

5. Divide both sides by 38

38x/38=-76/38

6. Simplfy

x=-2

6 0
2 years ago
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