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sesenic [268]
3 years ago
5

Question: when you subtract like terms how do you know what number to subtract from the other?

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
7 0

Answer: You would add them together, not subtract.

Step-by-step explanation: When you’re combining like terms, you always “add“ them together. For that example, you would add 3x and 10x together along with 4 and -9 together. That would look like (3x + 10x) + [4 + (-9)], which simplifies to 13x - 5 = 180.

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Simplify the expression.<br> (-2-2i)(-4+6i)
hoa [83]

Answer:

20 - 4i is the correct answer!

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which of the following polynomials has a remainder of 24 when divided by x+2?
Bad White [126]

Option C is the correct choice   -2x^4+4x^2+3x-2,

Remainder of a polynomial by substitution

For a polynomial f(x) to give a remainder of 24 when divided by x + 2:

f(-2) = 24

By testing, substitute x = -2 into the equation -2x^4+4x^2+3x-2

f(x) = -2x^3+4x^2+3x-2\\\\f(-2)=-2(-2)^3+4(-2)^2+3(-2)-2\\\\f(-2)=-2(-8)+4(4)-6-2\\\\f(-2)=16+16-8\\\\f(-2)=32-8\\\\f(-2)=24

Since f(-2) = 24 when x = -2 is substituted into  -2x^4+4x^2+3x-2, then  -2x^4+4x^2+3x-2 has a remainder of 24 when divided by x+2

Learn more on remainder of a polynomial here: brainly.com/question/24202892

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5 0
2 years ago
A man was traveling by air is allowed a maximum of 20kg luggages .The man has four bags weighing 3.5kg ,15 kg ,2kg and 1.5kg .Fi
KatRina [158]

Answer:

See explanation

Step-by-step explanation:

Maximum weight = 20 kg

Bag 1 = 3.5kg

Bag 2 = 15 kg

Bag 3 = 2kg

Bag 4 = 1.5kg

Total weight of bags = 22 kg

Excess weight of his luggage = Total weight of bags - Maximum weight

= 22 kg - 20 kg

= 2 kg

Express the excess weight as a percentage of his maximum weight allowed = excess weight / maximum weight × 100

= 2/20 × 100

= 0.1 × 100

= 10%

Express the excess weight as a percentage of his maximum weight allowed = 10%

5 0
3 years ago
Because of the commutative property of multiplication, it is true that
aliya0001 [1]

Answer:

30 x 4 + 4 x 4 and 4 x 4 + 4 x 30

Step-by-step explanation:

5 0
3 years ago
Solve the matrix and prove that it is equal 0​
Art [367]

Step-by-step explanation:

\underline{ \underline{ \text{Given}}}  :

  • \tt{ {A}^{T}  = \begin{bmatrix} 2 &  - 4 \\ 4 & 3 \\ \end{bmatrix}}

\underline{ \underline { \text{To \: Find}}} :

  • \sf{ {A}^{2}  - 5A+ 22I= 0}

\underline{ \underline{ \text{Solution}}} :

The new matrix obtained from a given matrix by interchanging it's rows and columns is called the transposition of matrix. It is denoted by \sf{ {A}^{T}}. Again , Interchange it's rows and columns in order to find ' A '.

\tt{A = \begin{bmatrix} 2 &  4 \\  - 4 & 3 \\ \end{bmatrix}}

Now , LEFT HAND SIDE ( L.H.S )

\tt{ {A}^{2}  - 5A+ 22I}

Here, I refers to identity matrix. A diagonal matrix in which all the elements of leading diagonal are 1 ( unit ) is called unit or identity matrix.

⟼ \begin{bmatrix} 2 &   4 \\  - 4 & 3 \\ \end{bmatrix} \times \begin{bmatrix} 2 &  4 \\ -  4 & 3 \\ \end{bmatrix} - 5 \times \begin{bmatrix} 2 &   4 \\  - 4 & 3 \\ \end{bmatrix} + 22 \times \begin{bmatrix} 1 &   0 \\  0 & 1\\ \end{bmatrix}

⟼ \begin{bmatrix} 2  \times 2 + 4 \times ( - 4)&   2  \times 4 + 4 \times 3 \\  - 4 \times 2 + 3 \times ( - 4) &  - 4  \times 4 + 3 \times 3 \\ \end{bmatrix} - \begin{bmatrix} 10 &   20 \\   - 20& 15 \\ \end{bmatrix} + \begin{bmatrix} 22 &   0 \\  0 & 22 \\ \end{bmatrix}

⟼ \begin{bmatrix} 4 + ( - 16) &   8 + 12 \\   - 8 + ( - 12) &  - 16 + 9 \\ \end{bmatrix} - \begin{bmatrix} 10 &   20 \\   - 20 & 15 \\ \end{bmatrix} + \begin{bmatrix} 22 &   0 \\  0 & 22 \\ \end{bmatrix}

⟼ \begin{bmatrix} - 12 &   20\\  - 20&  - 7 \\ \end{bmatrix} - \begin{bmatrix} 10 &   20 \\   - 20 & 15 \\ \end{bmatrix} + \begin{bmatrix} 22 &   0 \\  0 & 22 \\ \end{bmatrix}

⟼ \begin{bmatrix}  - 22 &   0 \\  0&  - 22 \\ \end{bmatrix}  + \begin{bmatrix} 22 &   0 \\  0 & 22 \\ \end{bmatrix}

⟼ \begin{bmatrix}  - 22 + 22 &   0 + 0 \\  0 + 0 &  - 22  + 22 \\ \end{bmatrix}

⟼ \begin{bmatrix} 0 &   0\\  0 & 0 \\ \end{bmatrix}

⟼ \sf{0}

RIGHT HAND SIDE ( R.H.S ) : 0

L.H.S = R.H.S [ Hence , proved ! ]

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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4 0
3 years ago
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