All categories

3 years ago

Question: when you subtract like terms how do you know what number to subtract from the other?

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

7 0

Answer: You would add them together, not subtract.

Step-by-step explanation: When you’re combining like terms, you always “add“ them together. For that example, you would add 3x and 10x together along with 4 and -9 together. That would look like (3x + 10x) + [4 + (-9)], which simplifies to 13x - 5 = 180.

You might be interested in

The difference between a number and 16 is 49. ANYBODY KNOW THE ANSWER?~

nekit [7.7K]

Hey there!

GUIDE

• The word “sum” means add

• The word “difference” means subtract

• The word “product” means multiply

• The word “quotient” means divide

• The word “is” means equal to

• The “unknown number” is a variable that is not known. So people usually label it as a variable until they figure out what the unknown value is.

Now that we have that information out the way we can solve for your given question.

“The [DIFFERENCE] between [a number] & 16 [is] 49

Lets break it down

• DIFFERENCE (between) = subtract☑️

• A NUMBER = UNKNOWN (so we will label it is as “n”]☑️

• 16 will stay the same because NOTHING was done to it!

• IS = is equal to☑️

We have the key terms out of the way so now we met our answer

ANSWER:

“n - 16 = 49”

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

5 0

2 years ago

What is 8x-12y+32= please help me!

adelina 88 [10]

X = -4
y = 0

8x-12y+32 = 24

8 0

3 years ago

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

Hence, Option (d) is correct.

6 0

2 years ago

Which equation represents this sentence? Five more than three times the number is one-third more than the sum of the number and

vesna_86 [32]

3x+5=(x+x)+.3 is the answer

7 0

3 years ago

Read 2 more answers

Of the 480 visitors on Saturday, 60% of them stayed until the park closed. About how many visitors stayed until the park closed?

bazaltina [42]

Answer:

288 visitors stayed

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers